Answer:
Step-by-step explanation:
<u>Given:</u>
- Volume of fuel = 5/6
- Volume of fuel used each time = 1/12
- Number of travels to or from work = x
<u>Since each time 1/12 of the tank is used, and initial volume is 5/6 of the tank, the equation will be:</u>
<u>Solving the equation we get:</u>
So Felitz can travel 10 times to/from work with 5/6 full tank
Answer: 21,952 cm³
Explanation:
Volume = 28 x 28 x 28 = 29 152 cm³
Answer: 18. 75
Step-by-step explanation:
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cp percent fraction sp
-12 88/100 16. 50
100*16.50 /88= 18.75
Subtract 379 from both sides.
that gives us: 
divide both sides by -24 which equals: x = 13.
13 weeks
Answer:
A. The bag weights for brand A have less variability than the bag weights for brand B.
Step-by-step explanation:
In a box plot display, measure of variability can be determined by the length of the rectangular box or/and by the length of the whiskers.
The longer or greater the length, the more the variability the data set has. The shorter or smaller the length, the lesser the variability.
The box plot display of Brand A has shorter rectangular box and a shorter whisker length compared to the box plot display of Brand B. Therefore, it can be concluded that: bag weights for Brand A have less variability compared to bag weights for Brand B.
The correct statement of comparison is:
"A. The bag weights for brand A have less variability than the bag weights for brand B."
Option B is incorrect. Bag weights for Brand A do not have more variability than those of Brand B.
Option C and option D are both incorrect. Neither an outlier nor range can be used to represent or describe "typical value" for a given data set.
Typical bag weights can be well represented or described by average bag weights or median weight of the data set.
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