Question

Andre has a bowl of chocolates where 70% of them are milk chocolate and the remaining 30% are

Answer 1

Answer:

4) 7.9%

Step-by-step explanation:

Given:

% of milk chocolate = 70%

% of white chocolate = 30%

Total number of chocolate = 20

Number of milk chocolate:

$\frac{70}{100} * 20 = 14$

Number of white chocolate:

$\frac{30}{100} * 20 = 6$

From the calculations, we now know there are 14 milk chocolates and 6 white chocolates.

2 white chocolates are picked at random without replacement.

Probability first chocolate picked was white: $\frac{6}{20} = 0.3$

Probability second chocolate picked was white: $\frac{5}{19} = 0.2632$

To find probability that both of them are white chocolates, multiply probability of the first and second.

0.3 * 0.2632 = 0.07896

≈ 0.079

Convert to percentage by multiplying by 100.

0.079 * 100 = 7.9%

The probability that they are both

white chocolate is 7.9%