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inessss [21]
2 years ago
7

Circle or highlight the six most common elements found in living things. Do the same thing for the five other elements that are

also found in the body in smaller quantities.
Hint: Think about the symbols for carbon, hydrogen, nitrogen, phosphorus, chorine, magnesium, sulfur, sodium, and potassium. ​

help very appreciated!!

Biology
1 answer:
MissTica2 years ago
4 0

Answer:

the 6 most common elements in living things are carbon, hydrogen, nitrogen, oxygen, phosphorus, and sulfur. 5 elements in the body are calcium, potassium, sodium, chlorine, and magnesium.

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Yanni made a chart to compare the strong and weak forces. Which best describes Yanni’s error? Only the weak force is active in t
cluponka [151]

Answer: Option (d) is the correct answer.

Explanation:

Nucleus of an atom consists of protons and neutrons. Protons are positively charged and neutrons have no charge. So, due to the like charges of protons there occurs electrostatic force of repulsion inside the nucleus of the atom.

But due to similar number of neutrons and protons a force that is able to bind both of them together is known as strong nuclear binding energy.

This force is strong enough that it is able to overcome electrostatic force of repulsion. But when there is great difference in the number of protons and neutrons then binding force is not strong enough.

Hence, the atom becomes unstable and undergoes radioactive decay. So, this means weak forces are responsible for radioactive decay.

Thus, we can conclude that the statement which best describes Yanni’s error is that the strong force is responsible for radioactive decay.

8 0
2 years ago
Read 2 more answers
1. Barney and Betty are about to have their first child. They both have "normal" feet but Barney's father has flat feet and Bett
Gnom [1K]
These are the correct answers to the following questions:

<span>1. Barney and Betty are about to have their first child. They both have "normal" feet but Barney's father has flat feet and Betty has a child from a previous marriage who has flat feet, meaning they are both heterozygous for the trait. What is the probability that they will have a boy with flat feet(recessive trait)?

A.25%
B.50%
C.100%
D.75%

2. humans, the ability to roll the tongue is a dominant trait. The inability to roll the tongue is a recessive trait. If two individuals homozygous recessive for this trait have a child, what is the chance that the child will be able to roll his tongue?

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4 0
2 years ago
'Main cause of depletion of ozone layer is human being ' Clarify this statement.​
disa [49]

Answer:

The ozone layer is being depleted due to CFC's. CFC's are found in aersoal spray cans and refrigants, when they are released into the atmosphere it causes depletion of the ozone layer. Humans are the one who made the CFC's, causing the ozone layer to deplete, even though they have been banned now, a lot of damage has been done.

Answer from Gauthmath

8 0
2 years ago
g Choose the correct answer from the list. Group of answer choices DNA sequences that are deduced by comparing many related DNA
REY [17]

Answer:

Explanation:

Group of answer choices DNA sequences that are deduced by comparing many related DNA sequences are called CONSENSUS. Unlike DNA synthesis, RNA synthesis requires TRANSCRIPTION. PROMOTERS direct RNA polymerase to the initiation site. RNA synthesis complexes containing DNA, RNA, and polymerase perform TRANSLATION. RNA synthesis (tRNA, mRNA, and rRNA) takes place in complexes containing DNA, RNA, and polymerase are called TRANSCRIPTION BUBBLES. The expression of beta-galactosidase requires the induction of operons by addition of REPRESSORS.

7 0
2 years ago
Two autosomal genes, J and K, are 60 map units apart. You perform the following testcross: J K / j k x j k / j k. At what freque
Dmitry [639]

Answer:

  • J K / j k = 20%
  • j k / j k = 20%
  • J k / j k = 30%
  • j K / j k = 30%                

Explanation:

To calculate the recombination frequency, we have to know that 1% of recombinations = 1 map unit = 1cm. And that the maximum recombination frequency is always 50%.

The map unit is the distance between the pair of genes for which every 100 meiotic products, one of them results in a recombinant one.

So, en the exposed example:

  • J and K are autosomal genes
  • J and K are separated by 60 M.U.
  • 60 M.U. means that there is 60% of recombination.

Cross)             J K / j k                    x                  j k / j k

Gametes) JK  Parental                                     jk, jk, jk, jk

                jk   Parental                                  

                Jk   Recombinant                          

                 jK   Recombinant

One map unit equals 1% of recombination frequency. This means that every 100 meiotic products, one of them is a recombinant one.

1 M.U. -------------- 1% recombination

60 M.U. ------------ 60% recombination

                              30% Jk  +  30% jK

100 M.U. - 60 M.U. = 40 M.U.

40M.U.--------------40 % Parental (Not recombinant)

                            20% JK   +   20% jk

Punnet Square)           JK       jk      Jk      jK

                          jk     JK/jk   jk/jk   Jk/jk   jK/jk

J K / j k = 20%

j k / j k = 20%

J k / j k = 30%

j K / j k = 30%                                

3 0
2 years ago
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