Answer:
a. Five-Carbon Sugar and Phosphate
Explanation:
A nucleotide can be defined as an organic molecule which forms the building block of nucleic acid such as deoxyribonucleic acid (DNA) and ribonucleic acid (RNA).
Basically, nucleotide comprises of the following parts;
1. Nitrogenous base: this includes adenine (A), thymine (T), guanine (G), and cytosine (C) which are mainly found in the DNA while adenine (A), guanine (G), uracil (U) and cytosine (C) are found in the RNA.
2. A phosphate group.
3. A penrose sugar: it is either deoxyribose in DNA or ribose in RNA.
The two parts or chemical components of a nucleotide which do not change throughout the structure of DNA are;
I. Five-Carbon Sugar also known as deoxyribose and it has hydrogen on its second carbon.
II. Phosphate: this is the structural backbone that provides support to DNA.
It would be A
First is: DNA > mRNA (messenger RNA) > tRNA (transfer RNA) > protein
Answer:
A. It contains fewer volatile gases.
Explanation:
Mafic lava have a composition of about 45-55% silica with high amount of Fe, Mg, Ca.
The silica content is quite low compared to those of granitic magma whose silica content can reach up to about 60%.
What determines the viscosity of magma is basically the silica content of the magma and the temperature of the magma. Viscosity is the resistance to flow.
The higher the silica content, the lower the viscosity and the higher the amount of volatile gases. Such type of magma is the granitic magma. Granitic magma due to their viscosity flows slowly.
The lower the silica content, the higher the viscosity and the lesser the presence of volatile gases in them. Such an example is Mafic magma. Mafic magma flows very slowly with low amount of dissolved gases.
Answer:
a. The formula for finding the number of colonies in a given volume is,
CFU/ml, here CFU is the colony forming units or the number of colonies formed in a volume plated in ml × dilution
The dilution factor given in the question is 1 × 10⁻⁴ and the number of colonies given is 186. Therefore, the number of bacteria present in the given 1 ml of the milk is,
CFU/ ml = 186 / 1 × 10⁻⁴ = 186 × 10⁴.
Hence, the concentration of bacteria in the milk is 186 × 10⁴ CFU/ml.
b) The limit of the bacterial concentration in the pasteurized milk is 20000 CFU/ml, however, it can be seen that the sample of the milk possess more concentration of bacteria than the desired value. Therefore, the milk is not safe to drink by Public Health Standards.
