answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
taurus [48]
2 years ago
15

One semester in a chemistry class, 14 students failed due to poor attendance, 23 failed due to not studying, 15 failed because t

hey did not turn in assignments, 9 failed because of poor attendance and not studying, 8 failed because of not studying and not turning in assignments, 5 failed because of poor attendance and not turning in assignments, and 2 failed because of all three of these reasons.
Required:
a. How many failed for exactly two of the three reasons?
b. How many failed because of poor attendance and not studying but not because of not turning in assignments?
c. How many failed because of exactly one of the three reasons?
d. How many failed because of poor attendance and not turning in assignments but not because of not studying?

Mathematics
1 answer:
BlackZzzverrR [31]2 years ago
7 0

Answer:

(a) 16 students failed for exactly two of the three reasons.

(b) 7 students failed because of poor attendance and not studying but not because of not turning in assignments.

(c) 14 students failed because of exactly one of the three reasons.

(d) 3 students failed because of poor attendance and not turning in assignments but not because of not studying.

Step-by-step explanation:

We are given that one semester in a chemistry class, 14 students failed due to poor attendance, 23 failed due to not studying, 15 failed because they did not turn in assignments, 9 failed because of poor attendance and not studying, 8 failed because of not studying and not turning in assignments, 5 failed because of poor attendance and not turning in assignments, and 2 failed because of all three of these reasons.

As shown in the diagram attached below, a Venn diagram represents the situation given in the question;

In the diagram below, 2 in represents purple color represents the number of students failed because of all three of these reasons.

7 represents the number of students who failed because of poor attendance and not studying but not due to not turning in assignments.

6 represents the number of students who failed because of not studying and not turning in assignments but not due to poor attendance.

3 represents the number of students who failed because of poor attendance and not turning in assignments but not due to not studying.

2 in red color represents the number of students who failed only due to poor attendance.

8 in red color represents the number of students who failed only due to not studying.

4 in red color represents the number of students who failed only due to not turning in assignments.

(a) The number of students who failed because of exactly two of the three reasons = 7 + 6 + 3 = 16 students.

(b) The number of students who failed because of poor attendance and not studying but not because of not turning in assignments = 9 - 2 = 7 students.

(c) The number of students who failed because of exactly one of the three reasons = 2 + 8 + 4 = 14 students.

(d) The number of students who failed because of poor attendance and not turning in assignments but not because of not studying = 5 - 2 = 3 students.

You might be interested in
Jake made a total of 7 copies at a copy shop, with some being black-and-white copies and some being color copies. Black-and-whit
Arada [10]
Jake spent a total of 70 cents.
b = black-and-white = 8 cents
c = color = 15 cents

70 = 8b + 15c

he made a total of 7 copies
b + c = 7

system of equation:
70 = 8b + 15c
b + c = 7

--------------------------

b + c = 7
b + c (-c) = 7 (-c)
b = 7 - c

plug in 7 - c for b

70 = 8(7 - c) + 15c
Distribute the 8 to both 7 and - c (distributive property)

70 = 56 - 8c + 15c
Simplify like terms

70 = 56 - 8c + 15c
70 = 56 + 7c

Isolate the c, do the opposite of PEMDAS: Subtract 56 from both sides

70 (-56) = 56 (-56) + 7c
14 = 7c

divide 7 from both sides to isolate the c

14 = 7c
14/7 = 7c/7
 c = 14/7
 c = 2

c = 2
---------------

Now that you know what c equals (c = 2), plug in 2 for c in one of the equations.
b + c = 7
c = 2
<em>b + (2) = 7
</em><em />Find b by isolating it. subtract 2 from both sides
b + 2 = 7
b + 2 (-2) = 7 (-2)
b = 7 - 2
b = 5

Jake made 5 black-and-white copies, and 2 color copies

hope this helps
8 0
2 years ago
Read 2 more answers
Rectangle ABCD with coordinates A(1,1), B(4,1), C(4,2) and D(1,2) dilates with respect to the origin to give rectangle A’B’C’D’.
Delvig [45]

Answer: Option C.

Step-by-step explanation:

You need to find the distance AB with the formula for calculate the distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Then, substituting the coordinates of the points A(1,1) and B(4,1), you get:

AB=\sqrt{(4-1)^2+(1-1)^2}=3

You know that A'B'=6, then the scale factor of dilation can be calculated with:

k=\frac{A'B'}{AB}

Substituting values, you get:

k=\frac{6}{3}\\\\k=2

This matches with the option C.

8 0
2 years ago
Read 2 more answers
Assume that the national average score on a standardized test is 1010, and the standard deviation is 200, where scores are norma
kotykmax [81]

Answer:

0.00

Step-by-step explanation:

If the national average score on a standardized test is 1010, and the standard deviation is 200, where scores are normally distributed, to calculate the probability that a test taker scores at least 1600 on the test, we should first to calculate the z-score related to 1600. This z-score is z=\frac{1600-1010}{200}=2.95, then, we are seeking P(Z > 2.95), where Z is normally distributed with mean 0 and standard deviation 1. Therefore, P(Z > 2.95) = 0.00

4 0
2 years ago
Read 2 more answers
For the angles α and β in the figures, find cos(α + β)?
Blababa [14]

Answer:

\cos(\alpha +\beta)=\frac{2}{3}(1-\frac{\sqrt{5}}{5})

Step-by-step explanation:

Let the hypotenuse of the smaller triangle be h units.

Then; from the Pythagoras Theorem.

h^2=4^2+2^2

h^2=16+4

h^2=20

h=\sqrt{20}

h=2\sqrt{5}

From the smaller triangle;

\cos (\alpha)=\frac{4}{2\sqrt{5} }=\frac{2}{\sqrt{5} } and \sin(\alpha)=\frac{2}{2\sqrt{5} }=\frac{1}{\sqrt{5} }

From the second triangle, let the other other shorter leg of the second triangle be s units.

Then;

s^2+4^2=6^2

s^2+16=36

s^2=36-16

s^2=20

s=\sqrt{20}

s=2\sqrt{5}

\cos(\beta)=\frac{2\sqrt{5} }{6}=\frac{\sqrt{5} }{3}

and

\sin(\beta)=\frac{4}{6}=\frac{2}{3}

We now use the double angle property;

\cos(\alpha +\beta)=\cos(\alpha)\cos(\beta) -\sin(\alpha)\sin(\beta)

we plug in the values to obtain;

\cos(\alpha +\beta)=\frac{2}{\sqrt{5} }\times \frac{\sqrt{5} }{3}-\frac{1}{\sqrt{5} }\times \frac{2}{3}

\cos(\alpha +\beta)=\frac{2}{3}(1-\frac{\sqrt{5}}{5})

3 0
2 years ago
Read 2 more answers
Select the factors of 6ab + 3ay − 2bx − xy.
V125BC [204]
Answer
<span>A. (3a − x)(2b + y)

cause

</span><span> (3a − x)(2b + y) = 6ab + 3ay -2bx -xy (expand by using distributive property)</span>
3 0
2 years ago
Read 2 more answers
Other questions:
  • A rectangle’s length is 2 units more than twice its width. Its area is 40 square units. The equation w(2w + 2) = 40 can be used
    9·3 answers
  • A rectangle is 5 √7 + 2 √3 meters long and 6 √7 - 3 √3 meters wide. a. Find the perimeter of the rectangle in simplest form. 2 b
    9·1 answer
  • Solve the formula for the specified variable. D=1/2fk for f <br>f=
    14·1 answer
  • Elio makes candles that are 14 cm tall. Each candle burns 8 hours before going out. He is wondering how many hours a 21 cm tall
    12·2 answers
  • Please help and explain
    12·1 answer
  • Minute Maid states that a bottle of juice contains 473 mL. Consumer groups are interested in determining if the bottles contain
    9·1 answer
  • The breaking strength of a rivet has a mean value of 10,050 psi and a standard deviation of 499 psi. (a) What is the probability
    8·2 answers
  • Factorise 125x^3 -27y^3
    13·1 answer
  • Trisha has 2 boxes of marbles. She selects a marble from each box 100 times, replacing the
    12·2 answers
  • Kevin gathered data from his classmates about the number of books they consulted and the total time they spent on a research pap
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!