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kvv77 [185]
2 years ago
14

Amy is biking to school from her father's house and Jeremy is biking to school from his aunt's house. Suppose Amy is moving at a

rate 10 miles per hour and Jeremy is moving at a rate of 8 miles per hour. Can you assume that Amy will get to school first? Explain.
Mathematics
2 answers:
Mnenie [13.5K]2 years ago
9 0

No, having the greater rate of change does not mean a function will necessarily reach an output with the smallest input. It also depends on the initial values of the functions. If Jeremy's aunt lives closer to school, Jeremy's rate of change is smaller, but he could still get to school before Amy.

Dovator [93]2 years ago
4 0

Answer:

No, having the greater rate of change does not mean a function will necessarily reach an output with the smallest input. It also depends on the initial values of the functions. If Jeremy's aunt lives closer to school, Jeremy's rate of change is smaller, but he could still get to school before Amy.

Step-by-step explanation:

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Does this table represent a function? Why or why not?
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C.No because two of the y values are the same

Step-by-step explanation:


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Ling lives 2 miles from school. It took him 15 minutes to bike from school to home. The first half of the distance he biked at a
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Tire pressure monitoring systems (TPMS) warn the driver when the tire pressure of the vehicle is 26% below the target pressure.
ZanzabumX [31]

Answer:

a) 22.94 psi

b) 5.93\times10^{-5}

Step-by-step explanation:

a)The pressure at which will trigger a warning is

31 - 31*0.26 = 22.94 psi

b) The probability that that the TPMS will trigger warning at 22.94 psi, given that tire pressure has a normal distribution with average of 31 psi and standard deviation of 2 psi

f(x)={\frac {1}{\sigma {\sqrt {2\pi }}}}e^{-{\frac {1}{2}}\left({\frac {x-\mu }{\sigma }}\right)^{2}}

where x = 22.94, \mu = 31, \sigma = 2

f(22.94)={\frac {1}{2 {\sqrt {2\pi }}}}e^{-{\frac {1}{2}}\left({\frac {22.94-31}{2 }}\right)^{2}}

f(22.94)=0.2e^{-8.12} = 5.93\times10^{-5}

6 0
2 years ago
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