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2 years ago

5

Someone needs to turn the crank to make the flywheel spin. Is this person creating energy? If not, where do you think the person

’s energy comes from?

1 answer:

barxatty [35]2 years ago

3 0

Answer:

the person is creating energy in their muscels but they are not making energy in their flywheel its only in their body

Explanation:

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At his review last year, Lucas was promised a 20 percent raise if he met his production goals. Raises were included in today’s p

Murrr4er [49]

Answer: Instrumentality;low

Explanation: Instrumentality is the impact a person have or will be able to render to a given activity or his or her job. The Instrumentality of a person has been found to be proportional to the what outcome of the person's efforts. Especially if the person's explanations are meant.

When a person's expectations are not meant it will cause the person's Instrumentality to be low.

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2 years ago

mechanically cleaned wastewater bar screen is constructed using 6.5-mm-wide bars spaced 5.0 cm apart center to center; the bars

Annette [7]

Answer: The head loss is 1.5 cm

Explanation: Equation needed to solve is: $h= (vs^2-v^2)/2gC^2$

where C is the friction coefficient. To determine the area of flow, we nee to realize that the area available for flow over an area of 1*1 m, Aₓ= 0.87 m², observed from the correlation that for every width of 5.0 cm, we lose 6.5 mm, roughly about 12.9 or 13%.

For a fresh clean screen, the velocity will tend to increase by a factor of (1/0.87).

The velocities through the screen equals to (0.4/0.87) = 0.46 m/s and (0.8/0.87) = 0.92 m/s.

Apply the above mentioned equation:

$h= (0.92^2-0.8^2)/2*0.84^2*9.81 \\\\=0.01499\\=0.015 m = 0.015*100 = 1.50 cm$

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2 years ago

In a production facility, 1.6-in-thick 2-ft × 2-ft square brass plates (rho = 532.5 lbm/ft3 and cp = 0.091 Btu/lbm·°F) that are

Gnoma [55]

Answer:

106600 btu/s

<u>note: </u>

<u><em> solution is attached due to error in mathematical equation. please find the attachment</em></u>

8 0

2 years ago

. A belt drive is desired to couple the motor with a mixer for processing corn syrup. The 25-hp electric motor is rated at 950 r

forsale [732]

Answer:

Hello the table which is part of the question is missing and below are the table values

For a 5V belt the available diameters are : 5.5, 5.8, 5.9, 6.2, 6.3, 6.6, 12.5, 13.9, 15.5, 16.1, 18.5, 20.1

Answers:

belt size = 140 in with diameter of 20.1n

actual speed of belt = 288.49 in/s

actual center distance = 49.345 in

Explanation:

Given data :

Electric motor (driver sheave) speed (w1) = 950 rpm

Driven sheave speed (w2) = 250 rpm

pick D1 ( diameter of driver sheave) = 5.8 in ( from table )

To select an appropriate belt size we apply the equation for the velocity ratio to get the diameter first

VR = $\frac{w1}{w2}$ = 950 / 250

also since the speed of belt would be constant then ;

Vb = w1r1 = w2r2 ------- equation 1

r = d/2

substituting the value of r into equation 1

equation 2 becomes : $\frac{w1}{w2} = \frac{d2}{d1}$ = VR

Appropriate belt size ( d2) can be calculated as

d2 = $\frac{w1d1}{w2}$ = $\frac{950 * 5.8}{250}$ = 22.04

From the given table the appropriate belt size would be : 20.1 because it is the closest to the calculated value

next we have to determine the belt length /size

$L = 2C + \frac{\pi }{2} ( d1+d2) + \frac{(d2-d1)^2}{4C}$

inputting all the values into the above equation including the value of C as calculated below

L ≈ 140 in

Calculating the center distance

we use this equation to get the ideal center distance

$d2< C_{ideal} < 3( d1 +d2)$

22.04 < c < 3 ( 5.8 + 20.1 )

22.04 < c < 77.7

the center distance is between 22.04 and 77.7 but taking an average value

ideal center distance would be ≈ 48 in

To calculate the actual center distance we use

$C = \frac{B+\sqrt{B^2 - 32(d2-d1)^2} }{16}$ -------- equation 3

B = $4L -2\pi (d2 + d1 )$

inputting all the values into (B)

B = 140(4) - 2 $\pi$ ( 20.01 + 5.8 )

B ≈ 399.15 in

inputting all the values gotten Back to equation 3 to get the actual center distance

C = 49.345 in ( actual center distance )

Calculating the actual belt speed

w1 = 950 rpm = 99.48 rad/s

belt speed ( Vb) = w1r1 = w1 * $\frac{d1}{2}$

= 99.48 * 5.8 / 2 = 288.49 in/s

3 0

2 years ago

A 60-cm-high, 40-cm-diameter cylindrical water tank is being transported on a level road. The highest acceleration anticipated i

dlinn [17]

Answer:

$h_{max} = 51.8 cm$

Explanation:

given data:

height of tank = 60cm

diameter of tank =40cm

accelration = 4 m/s2

suppose x- axis - direction of motion

z -axis - vertical direction

$\theta$ = water surface angle with horizontal surface

$a_x =$ accelration in x direction

$a_z =$ accelration in z direction

slope in xz plane is

$tan\theta = \frac{a_x}{g +a_z}$

$tan\theta = \frac{4}{9.81+0}$

$tan\theta =0.4077$

the maximum height of water surface at mid of inclination is

$\Delta h = \frac{d}{2} tan\theta$

$=\frac{0.4}{2}0.4077$

$\Delta h 0.082 cm$

the maximu height of wwater to avoid spilling is

$h_{max} = h_{tank} -\Delta h$

= 60 - 8.2

$h_{max} = 51.8 cm$

the height requird if no spill water is $h_{max} = 51.8 cm$

3 0

2 years ago