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zalisa [80]
2 years ago
10

referring to either the CMS file or code book index, what is the cross reference for reduction of a dislocation?

Engineering
1 answer:
Oksi-84 [34.3K]2 years ago
4 0

Answer:

reposition

Explanation:

if you go to your icd 10 pcs index located on page 1 then  look up reduction the subterm is of a dislocation which leads you to the answer reposition

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The procedure for determining the presence of Non-Condensable Gasses in refrigerant contained in an external recovery tank utili
natta225 [31]

Answer:

The procedure for determining the presence of non-condensable gases in refrigerant contained in an external recovery tank utilizes the principle that non-condensable gases increases the pressure of the refrigerant (compared to the saturation pressure).

Explanation:

The existence of non-condensable gases gives rise to an increase in the pressure of the refrigerant, this generates supplementary thermal resistance in the refrigeration circuit, which in turn decreases the efficiency of the system.

6 0
2 years ago
Read 2 more answers
Compute the mass fractions of α ferrite and cementite in pearlite. Assume T=726⁢ C∘.
kotykmax [81]

Answer:

The mass composition of ∝ ferrite is 88.94%.

The mass composition of cementite is 11.05%.

Explanation:

Given that

T=726 °C

We have to find the mass fractions of ferrite nad cementite in pearlite.

Lets take data from ideal Iron -carbon diagram at 726 °C

Composition of ∝ ferrite=0.022 5

Composition of pearlite =0.76 %

Composition of cementite =7.6%

We know that if we want to find the mass fraction the  we use Lever rule .So now by using lever rule

The\ mass\ composition\ of\alpha \ ferrite =\dfrac{6.7-0.76}{6.7-0.022}

So the mass composition of ∝ ferrite is 88.94%.

The\ mass\ composition\ of\ cementite =\dfrac{0.76-0.022}{6.7-0.022}

So the mass composition of cementite is 11.05%.

4 0
2 years ago
Discuss your interpretation of the confidence-precision trade-off, and provide a few examples of how you might make a choice in
LenKa [72]

The given question is incomplete, the complete question is as follows:

Our text describes a trade-off that we must make as engineers between our confidence in the value of a parameter versus the precision with which we know the value of that parameter. That trade-off might be affected by whether we are looking at a two-sided or bounded (one-sided) interval.

Question: Discuss your interpretation of the confidence-precision trade-off, and provide a few examples of how you might make a choice in one direction or the other in an engineering situation.

Answer: A balancing point is required to be reached to obtain a better confidence level in the predicted values.

Explanation:

The confidence interval and precision are the two terms that aims at providing the accurate estimation of the measurability of an object. If the precision increases, we can compromise on the confidence level and if the confidence level increases, then the precision of the predicted value also dilutes.

Thus a balance point is required to be reached between these two variables so that we get better confidence in the values being predicted without losing the correct estimation on precision. Ensuring that both the confidence and precision are maintained.

8 0
2 years ago
Link BD consists of a single bar 36 mm wide and 18 mm thick. Knowing that each pin has a 12-mm diameter, determine the maximum v
MAXImum [283]

Answer:

hello the diagram attached to your question is missing attached below is the missing diagram

answer :

a) 48.11 MPa

b) - 55.55 MPa

Explanation:

First we consider the equilibrium moments about point A

∑ Ma = 0

( Fbd * 300cos30° ) + ( 24sin∅ * 450cos30° ) - ( 24cos∅ * 450sin30° ) = 0

therefore ;<em> Fbd = 36 ( cos ∅tan30° - sin∅ ) kN  ----- ( 1 )</em>

A ) when ∅ = 0

Fbd = 20.7846 kN

link BD will be under tension when ∅ = 0, hence we will calculate the loading area using this equation

A = ( b - d ) t

b = 12 mm

d = 36 mm

t = 18

therefore loading area ( A ) = 432 mm^2

determine the maximum value of average normal stress in link BD  using the relation below

бbd = \frac{Fbd}{A}  = 20.7846 kN / 432 mm^2  =  48.11 MPa

b) when ∅ = 90°

Fbd = -36 kN

the negativity indicate that the loading direction is in contrast to the assumed direction of loading

There is compression in link BD

next we have to calculate the loading area using this equation ;

A = b * t

b = 36mm

t = 18mm

hence loading area = 36 * 18 = 648 mm^2

determine the maximum value of average normal stress in link BD  using the relation below

бbd = \frac{Fbd}{A} = -36 kN / 648mm^2 = -55.55 MPa

4 0
1 year ago
Theorems of Pappus and Guldinus are used to find: a. The surface area and volume of a body of rotation b. The surface area and v
s2008m [1.1K]

Answer:

option (a). The surface area and volume of a body of rotation

is the correct option

Explanation:

Theorems of Pappus and Guldinus are used to find the surface area and volume of a revolving body. It is neither applicable for surface areas and volumes of a symmetric body nor it helps to find the overall mass of any body. Thus, it can help to calculate the surface area and volume of any body rotated in 2-D frame(or any 2-D curve).

It is given or calculated as the product of area, perpendicular distance from the axis and length of the 2-D curve.

6 0
2 years ago
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