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borishaifa [10]
2 years ago
14

Theorems of Pappus and Guldinus are used to find: a. The surface area and volume of a body of rotation b. The surface area and v

olume of a symmetrical body c. The overall mass of a body d. None of the above
Engineering
1 answer:
s2008m [1.1K]2 years ago
6 0

Answer:

option (a). The surface area and volume of a body of rotation

is the correct option

Explanation:

Theorems of Pappus and Guldinus are used to find the surface area and volume of a revolving body. It is neither applicable for surface areas and volumes of a symmetric body nor it helps to find the overall mass of any body. Thus, it can help to calculate the surface area and volume of any body rotated in 2-D frame(or any 2-D curve).

It is given or calculated as the product of area, perpendicular distance from the axis and length of the 2-D curve.

You might be interested in
. A cylindrical metal specimen having an original diameter of 12.8 mm (0.505 in.) and gauge length of 50.80 mm (2.000 in.) is pu
kogti [31]

Answer:

% reduction in area==PR=0.734=73.4%

% elongation=EL=0.42=42%

Explanation:

given do=12.8 mm

df=6.60

Lf=72.4 mm

Lo=50.8 mm

% reduction in area=((\pi*(do/2)^2)-(\pi*(df/2)^2)))/\pi*(do/2)^2

substitute values

% reduction in area=73.4%

% elongation=EL=((Lf-Lo)/Lo))*100

% elongation=((72.4-50. 8)/50.8)*100=42%

6 0
2 years ago
A 227 pound compressor is supported by four legs that contact the floor of a machine shop. At the bottom of each leg there is a
Ganezh [65]

Answer:

1.312 in

Explanation:

Data provided in the question:

Weight of the compressor, W = 227 pound

Number of legs = 4

Maximum pressure = 42 psi

Now,

Let F be the force taken by the legs

Therefore,

W = 4F

or

227 pound = 4F

or

F = 56.75 pounds

Also,

Force = Pressure × Area

or

56.75 pounds = 42 psi × πr²                      [ r is the diameter of one leg]

or

r² = 0.4301

or

r = 0.656

therefore,

diameter = 2r = 2 × 0.656

= 1.312 in

6 0
2 years ago
A 20 dBm power source is connected to the input of a directional coupler having a coupling factor of 20 dB, a directivity of 35
lukranit [14]

Answer:

P_O = 0.989 watt = 19.9 dBm

Explanation:

Given data:

P_1 power = 20 dBm  = 0.1 watt

coupling factor is 20dB

Directivity = 35 dB

We know that

coupling factor = 10 log \frac{P_1}{P_f}

solving for  final power

20 = 10 log\frac{P_1}{P_f}

2 = log \frac{P_1}{P_f}

100 = \frac{0.1}{P_f}

P_f = 0.001 watt = 0 dBm

Directivity D =  10 \frac{P_f}{P_b}

35 = 10 \frac{0.001}{P_b}

P_b = 3.162 \times 10^{-7} wattt

output Power  = P_1 -P_f - P_b

                       = 0.1 - 0.001 - 3.162 \times 10^{-7}

P_O = 0.989 watt = 19.9 dBm

6 0
2 years ago
Instructions given by traffic police or construction flaggers _____. A. Are sometimes important to follow B. Are usually not imp
Anestetic [448]

Answer:

D. Overrule any other laws and traffic control devices.

Explanation:

Laws and traffic control devices are undoubtedly compulsory to be followed at every point in time to control traffic and other related situations. However, there are cases when certain instructions overrule these laws and traffic control devices. For example, when a traffic police is giving instructions, and though the traffic control devices too (such as traffic lights) are displaying their own preset lights to control some traffic, the instructions from the traffic police take more priority. This is because at that point in time, the instructions from the traffic control devices might not be just applicable or sufficient.

Also, in the case of instructions given by construction flaggers, these instructions have priority over those from controlling devices. This is because during construction traffic controls are redirected from the norms. Therefore, the flaggers such be given more importance.

6 0
2 years ago
A rectangular tank is filled with water to a depth of 1.5 m. Its longest side measures 2.5 m. What is the moment of the force ab
marishachu [46]

Answer:

The correct answer is option 'c': 13.8 kNm

Explanation:

We know that moment of a force equals

Moment=Force\times Arm

The hydro static force is given by Force=Pressure\times Area

We know that the hydrostatic pressure on a rectangular surface in vertical position is given by Pressure=\rho \times g\times h_{c.g}

For the given rectangular surface we have h_{c.g}=\frac{h}{2}=\frac{1.5}{2}=0.75m

Thus applying the values we get force as

Force=1000\times 9.81\times 0.75\times 1.5\times 2.5=27.59kN

This pressure will act at center of pressure of the rectangular plate whose co-ordinates is given by h/3 from base

Thus applying the calculated values we get

Moment=27.59\times \frac{1.5}{3}=13.8kN.m

8 0
2 years ago
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