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bekas [8.4K]
2 years ago
6

A rectangular tank is filled with water to a depth of 1.5 m. Its longest side measures 2.5 m. What is the moment of the force ab

out the base on this side? Is it. a) 5.5 kN.m b) 9.2 kN.m c) 13.8 kN.m d) 27.6 kN.m e) 41.4 kN.m
Engineering
1 answer:
marishachu [46]2 years ago
8 0

Answer:

The correct answer is option 'c': 13.8 kNm

Explanation:

We know that moment of a force equals

Moment=Force\times Arm

The hydro static force is given by Force=Pressure\times Area

We know that the hydrostatic pressure on a rectangular surface in vertical position is given by Pressure=\rho \times g\times h_{c.g}

For the given rectangular surface we have h_{c.g}=\frac{h}{2}=\frac{1.5}{2}=0.75m

Thus applying the values we get force as

Force=1000\times 9.81\times 0.75\times 1.5\times 2.5=27.59kN

This pressure will act at center of pressure of the rectangular plate whose co-ordinates is given by h/3 from base

Thus applying the calculated values we get

Moment=27.59\times \frac{1.5}{3}=13.8kN.m

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Use the drop -down menus to select the appropriate question type. Picking between two possible alternatives: Showing an understa
lora16 [44]

Answer:

Picking between two possible alternatives:

✔ true/false

Showing an understanding of relationships between facts:

✔ matching

Discussing a topic from a personal perspective:

✔ short answer / essay

Demonstrating factual knowledge by eliminating wrong answers and selecting the correct one:

✔ multiple choice

Explanation:

I got it right on edge. have a good day!

9 0
2 years ago
Write cout statements with stream manipulators that perform the following:
Semenov [28]

Answer:

A)cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B)cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C)cout<<fixed<<5.789E12;

D)cout<<left<<setw(7)<<67;

Explanation:

Stream Manipulators are functions specifically designed to be used in conjunction with the insertion (<<) and extraction (>>) operators on stream objects in C++ programming while the 'cout' statement is used to display the output of a C++to the standard output device.

setw:  used to specify the minimum number of character positions on the output field

setprecision: Sets the decimal precision to be used to format floating-point values on output operations.

fixed:  is used to set the floatfield format flag for the specified str stream.

left: adjust output to the left.

A) To display the number 34.789 in a field of eight spaces with two decimal places of precision. cout<<setw(9)<<fixed<<setprecision(2)<<34.789;

B) To display the number 7.0 in a field of six spaces with three decimal places of precision. cout<<setw(5)<<fixed<<setprecision(3)<<7.0;

C) To print out the number 5.789e+12 in fixed-point notation.  cout<<fixed<<5.789E12;

(D) To display the number 67 left-justified in a field of six spaces. cout<<left<<setw(7)<<67;

7 0
2 years ago
Discuss your interpretation of the confidence-precision trade-off, and provide a few examples of how you might make a choice in
LenKa [72]

The given question is incomplete, the complete question is as follows:

Our text describes a trade-off that we must make as engineers between our confidence in the value of a parameter versus the precision with which we know the value of that parameter. That trade-off might be affected by whether we are looking at a two-sided or bounded (one-sided) interval.

Question: Discuss your interpretation of the confidence-precision trade-off, and provide a few examples of how you might make a choice in one direction or the other in an engineering situation.

Answer: A balancing point is required to be reached to obtain a better confidence level in the predicted values.

Explanation:

The confidence interval and precision are the two terms that aims at providing the accurate estimation of the measurability of an object. If the precision increases, we can compromise on the confidence level and if the confidence level increases, then the precision of the predicted value also dilutes.

Thus a balance point is required to be reached between these two variables so that we get better confidence in the values being predicted without losing the correct estimation on precision. Ensuring that both the confidence and precision are maintained.

8 0
2 years ago
what is the advantage of decreasing the field current of a separately excited dc motor below its nominal value
enyata [817]

Answer:

Ability to rotate at higher speeds

Explanation:

Constant K1 becomes greater than the other constant K2

This translates to that the motor being able to rotate at high speeds, without necessarily exceeding the nominal armature voltage.

The armature voltage is the voltage that is developed around the terminals of the armature winding of an Alternating Current, i.e AC or a Direct Current, i.e DC machine during the period in which it tries to generate power.

6 0
2 years ago
The pump of a water distribution system is powered by a 6-kW electric motor whose efficiency is 95 percent. The water flow rate
Sonja [21]

Answer:

a) Mechanical efficiency (\varepsilon)=63.15%  b) Temperature rise= 0.028ºC

Explanation:

For the item a) you have to define the mechanical power introduced (Wmec) to the system and the power transferred to the water (Pw).

The power input (electric motor) is equal to the motor power multiplied by the efficiency. Thus, Wmec=0.95*6kW=5.7 kW.

Then, the power transferred (Pw) to the fluid is equal to the flow rate (Q) multiplied by the pressure jump \Delta P. So P_W = Q*\Delta P=0.018m^3/s * 200x10^3 Pa=3600W.

The efficiency is defined as the ratio between the output energy and the input energy. Then, the mechanical efficiency is \varepsilon=3.6kW/5.7kW=0.6315=63.15\%

For the b) item you have to consider that the inefficiency goes to the fluid as heat. So it is necessary to use the equation of the heat capacity but in a "flux" way. Calling <em>H</em> to the heat transfered to the fluid, the specif heat of the water and \rho the density of the water:

[tex]H=(5.7-3.6) kW=\rho*Q*c*\Delta T=1000kg/m^3*0.018m^3/s*4186J/(kg \ºC)*\Delta T[/tex]

Finally, the temperature rise is:

\Delta T=2100/75348 \ºC=0.028 \ºC

7 0
2 years ago
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