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Gekata [30.6K]
1 year ago
5

George is replacing a burned out resistor in a circuit board. The board has a 10, a 20, and a 40 on resistor, all in parallel. W

hen George has sided in the new component in the circuit is fixed, he checks his multimeter. What reading does he get?
Engineering
1 answer:
Marianna [84]1 year ago
7 0

Answer:gay

Explanation:

You might be interested in
referring to either the CMS file or code book index, what is the cross reference for reduction of a dislocation?
Oksi-84 [34.3K]

Answer:

reposition

Explanation:

if you go to your icd 10 pcs index located on page 1 then  look up reduction the subterm is of a dislocation which leads you to the answer reposition

4 0
2 years ago
3/63 A 2‐kg sphere S is being moved in a vertical plane by a robotic arm. When the angle θ is 30°, the angular velocity of the a
miss Akunina [59]

Answer:

Ps=19.62N

Explanation:

The detailed explanation of answer is given in attached files.

5 0
2 years ago
Bananas are to be cooled from 28°C to 12°C at a rate of 1140 kg/h by a refrigerator that operates on a vapor-compression refrige
Lera25 [3.4K]

Answer:

A) COP = \frac{16.97}{9.8} = 1.731

B) P_{IN} = 0.4763

C) Second law efficiency 4.85%

exergy destruction for the cycle = 9.3237 kW

Explanation:

Given data:

T_1 = 28 degree celcius

T_2 = 12 degree celcius

\dot m = 1140 kg/h

Power to refrigerator = 9.8 kW

Cp = 3.35 kJ/kg degree C

A) Q = \dot m Cp \Delta T

        = 1140 \times 3.35\times (28-12) = 61,104 kJ/h

Q_{abs} = 61,104 kJ/h = 16.97 kJ/sec

COP = \frac{16.97}{9.8} = 1.731

b)

COP ∝ \frac{1}{P_{in}}

P_{in} wil be max when COP maximum

taking surrounding temperature T_H = 20 degree celcius

COP_{max} = \frac{T_L}{T_H- T_L} = \frac{285}{293 - 285} = 35.625

we know that

COP = \frac{heat\ obsorbed}{P_{in}}

P_{IN} = \frac{16.97}{35.62} = 0.4763

c) second law efficiency

\eta_{11} = \frac{COP_R}{(COP)_max} = \frac{1.731}{35.625} = 4.85\%

exergy destruction os given as X = W_{IN} - X_{Q2}

                                                         = 9.8 - 0.473 = 9.3237 kW

8 0
2 years ago
Peter the postman became bored one night and, to break the monotony of the night shift, he carried out the following experiment
aleksandrvk [35]

Answer:

//This Program is written in C++

// Comments are used for explanatory purpose

#include <iostream>

using namespace std;

enum mailbox{open, close};

int box[149];

void closeAllBoxes();

void OpenClose();

void printAll();

int main()

{

closeAllBoxes();

OpenClose();

printAll();

return 0;

}

void closeAllBoxes()

{

for (int i = 0; i < 150; i++) //Iterate through from 0 to 149 which literarily means 1 to 150

{

box[i] = close; //Close all boxes

}

}

void OpenClose()

{

for(int i = 2; i < 150; i++) {

for(int j = i; j < 150; j += i) {

if (box[j] == close) //Open box if box is closed

box[j] = open;

else

box[j] = close; // Close box if box is opened

}

}

// At the end of this test, all boxes would be closed

}

void printAll()

{

for (int x = 0; x < 150; x++) //use this to test

{

if (box[x] = 1)

{

cout << "Mailbox #" << x+1 << " is closed" << endl;

// Print all close boxes

}

}

}

Explanation:

7 0
2 years ago
A water pump increases the water pressure from 15 psia to 70 psia. Determine the power input required, in hp, to pump 1.5 ft3/s
svetoff [14.1K]

Answer:

11.52 hp

Explanation:

<u><em>Givens: </em></u>

p_1  = 15 pisa

p_2  = 70 pisa

V_ol=1.5 ft^3/s

<u><em>Solution:  </em></u>

Note: m = p x V_ol (assuming in compressible flow —> p =const)  

The total change in the system mechanical energy can be calculated as follows,  

Δ e= (p_2 - p_1 ) /p

The power needed can be calculated as follows

P = W =mΔ e  = p x  V_ol x(p_2 - p_1 ) /p

  = V_ol x (p_2 - p_1 )

  = 44 pisa. ft^3/s

  = 44 x (1 btu/5.404pisa. ft^3) x (1 hp/0.7068btu/s)

  = 11.52 hp

3 0
2 years ago
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