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WITCHER [35]
2 years ago
5

A water pump increases the water pressure from 15 psia to 70 psia. Determine the power input required, in hp, to pump 1.5 ft3/s

of water. Does the water temperature at the inlet have any significant effect on the required flow power?
Engineering
1 answer:
svetoff [14.1K]2 years ago
3 0

Answer:

11.52 hp

Explanation:

<u><em>Givens: </em></u>

p_1  = 15 pisa

p_2  = 70 pisa

V_ol=1.5 ft^3/s

<u><em>Solution:  </em></u>

Note: m = p x V_ol (assuming in compressible flow —> p =const)  

The total change in the system mechanical energy can be calculated as follows,  

Δ e= (p_2 - p_1 ) /p

The power needed can be calculated as follows

P = W =mΔ e  = p x  V_ol x(p_2 - p_1 ) /p

  = V_ol x (p_2 - p_1 )

  = 44 pisa. ft^3/s

  = 44 x (1 btu/5.404pisa. ft^3) x (1 hp/0.7068btu/s)

  = 11.52 hp

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The closed tank of a fire engine is partly filled with water, the air space above being under pressure. A 6 cm bore connected to
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Answer:

The air pressure in the tank is 53.9 kN/m^{2}

Solution:

As per the question:

Discharge rate, Q = 20 litres/ sec = 0.02\ m^{3}/s

(Since, 1 litre = 10^{-3} m^{3})

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Height, h_{roof} = 2.5\ m

Now,

The velocity in the bore is given by:

v = \frac{Q}{\pi (\frac{d}{2})^{2}}

v = \frac{0.02}{\pi (\frac{0.06}{2})^{2}} = 7.07\ m/s

Now, using Bernoulli's eqn:

\frac{P}{\rho g} + \frac{v^{2}}{2g} + h = k                  (1)

The velocity head is given by:

\frac{v_{roof}^{2}}{2g} = \frac{7.07^{2}}{2\times 9.8} = 2.553

Now, by using energy conservation on the surface of water on the roof and that in the tank :

\frac{P_{tank}}{\rho g} + \frac{v_{tank}^{2}}{2g} + h_{tank} = \frac{P_{roof}}{\rho g} + \frac{v_{tank}^{2}}{2g} + h_{roof} + H_{loss}

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What is the physical significance of the Reynolds number?. How is defined for external flow over a plate of length L.
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Answer:

Re=\dfrac{\rho\ v\ l}{\mu }

Explanation:

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Reynolds number is a dimensionless number.Reynolds number given is the ratio of inertia force to the viscous force.

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For plate can be given as

Re=\dfrac{\rho\ v\ l}{\mu }

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Reynolds\ number\is \

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