Answer: The electric field decreases because of the insertion of the Teflon.
Explanation:
If the charge on the capacitor is held fixed, the electric field as a consequence of this charge distribution (directed from the positive charged plate to the negative charged one remains unchanged.
However, as the Teflon is a dielectric material, even though doesn't allow the free movement of the electrons as an answer to an applied electric field, it allows that the electrons be displaced from the equilibrium position, leaving a local negative-charged zone close to the posiitive plate of the capacitor, and an equal but opposite charged layer close to the negative plate.
In this way, a internal electric field is created, that opposes to the external one due to the capacitor, which overall effect is diminishing the total electric field, reducing the voltage between the plates, and increasing the capacitance proportionally to the dielectric constant of the Teflon.
Answer: Instrumentality;low
Explanation: Instrumentality is the impact a person have or will be able to render to a given activity or his or her job. The Instrumentality of a person has been found to be proportional to the what outcome of the person's efforts. Especially if the person's explanations are meant.
When a person's expectations are not meant it will cause the person's Instrumentality to be low.
Answer:
A RCRA characteristic hazardous waste is a solid waste that exhibits at least one of four characteristics defined in 40 CFR Part 261 subpart C — ignitability (D001), corrosivity (D002), reactivity (D003), and toxicity (D004 - D043). combustible, or have a flash point less than 60 °C (140 °F).
Answer:
The force would be 57.8 N if it was applied at a 30-degree angle from perpendicular.
Explanation:
We know that torque and force are represented by the following equation
τ = r x F sinθ ---- (1)
where τ is Torque, r is radius, F is force and θ is the angle between the force and lever arm.
Given data:
F = 50 N
r = 0.2 m
we have to find the force when θ = 30°
Putting these values in equation 1, we get
τ = 0.2 x 50 x sin(90°)
τ = 10 Nm
so Torque is 10 Nm
Now we will calculate the force was applied at a 30 degree angle from perpendicular, in this case the equation 1 becomes as
τ = r x F cosθ
Putting the values of τ , r, θ and F in above equation
10 = 0.2 x F x cos(30°)
Rearranging the above equation
F = 10 / (0.2 x cos (30°))
F = 10 / 0.173
F = 57.8 N
