All categories

2 years ago

Given the equation −4Square root of x minus 3 = 12, solve for x and identify if it is an extraneous solution.

Mathematics

2 answers:

Darina [25.2K]2 years ago

4 0

Answer:

There is no solution for the given radical equation.

x = 225/16 is an extraneous solution.

Step-by-step explanation:

The given equation is

Add 3 to both sides of the equation

Squaring both sides

Divide both sides by 16

Substituting back the value of x in original equation to check the extraneous solution.

Since -18≠ 12. Hence, the value of x does not satisfy the equation.

Therefore, x = 225/16 is an extraneous solution.

Step-by-step explanation:

zhannawk [14.2K]2 years ago

4 0

Answer:

yes i do have the answer i wat you to up the points

You might be interested in

Use lagrange multipliers to find the points on the given surface that are closest to the origin. y2 = 64 + xz

Inessa [10]

The distance between an arbitrary point on the surface and the origin is

$d(x,y,z)=\sqrt{x^2+y^2+z^2}$

Recall that for differentiable functions $g(x)$ and $h(x)$ , the composition $g(h(x))$ attains extrema at the same points that $h(x)$ does, so we can consider an augmented distance function

$D(x,y,z)=x^2+y^2+z^2$

The Lagrangian would then be

$L(x,y,z,\lambda)=x^2+y^2+z^2+\lambda(y^2-64-xz)$

We have partial derivatives

$\begin{cases}L_x=2x-\lambda z\\L_y=2y+2y\lambda\\L_z=2z-\lambda x\\L_\lambda=y^2-64-xz\end{cases}$

Set each partial derivative to 0 and solve the system to find the critical points.

From the second equation it follows that either $y=0$ or $\lambda=-1$ . In the first case we arrive at a contradiction (I'll leave establishing that to you). If $\lambda=-1$ , then we have

$\begin{cases}2x+z=0\\2z+x=0\end{cases}\implies x=0,z=0$

This means $y^2=64\implies y=\pm8$

so that the points on the surface closest to the origin are $(0,\pm8,0)$ .

8 0

2 years ago

Simplify 12¹⁶/12⁴ .

Klio2033 [76]

$12^{12}$

subtract 4 from 16.

8 0

2 years ago

Read 2 more answers

Pete traveled 1,380 miles in two days.The first day , he traveled 1.5 times as far as he did the second day . How many miles did

ahrayia [7]

Let s be the distance traveled the second day.

1.5s+s=1380

2.5s=1380

s=552

So on the first day he traveled 1380-552=828 miles.

6 0

2 years ago

Read 2 more answers

A veterinarian's office recorded one particular week that they had 50 patients. The following table shows the recorded number of

Gre4nikov [31]

Answer:

1. The correct answer is 46%

2. The correct answer is .07

3. The correct answer is (34%,58%)

4. The correct answer is (32%,60%)

Step-by-step explanation:

1. Let's calculate the percentage or proportion of patients that were dogs:

p = (7 + 4 + 5 + 5 + 2)/50 = 23/50 = 0.46

The correct answer is 46%

2. Let's estimate the standard error, using the given formula, this way:

S.e = √ (0.46 * 0.54)/50 = √0.049 = 0.07

The correct answer is .07

3. Let's calculate the confidence limits of the 90% confidence interval, this way:

Confidence limits = proportion +/- 1.645 * standard error

Confidence limits = 0.46 +/- 1.645 * 0.07

Confidence limits = 0.46 +/- 0.12

Confidence limits = 0.34, 0.58

The correct answer is (34%,58%)

4. Let's calculate the confidence limits of the 95% confidence interval, this way:

Confidence limits = proportion +/- 1.96 * standard error

Confidence limits = 0.46 +/- 1.96 * 0.07

Confidence limits = 0.46 +/- 0.14

Confidence limits = 0.32, 0.60

The correct answer is (32%,60%)

3 0

2 years ago

Type the correct answer in each box. Spell all the words correctly, and use numerals instead of words for numbers. If necessary,

Morgarella [4.7K]

Answer:

We can show that ∆ABC is congruent to ∆A′B′C′ by a translation of (x-2, y) unit(s) and a across the x-axis.

Step-by-step explanation:

The triangle ABC is shown in the image attached. The coordinates of the triangle are A(8, 8), B(10, 4), C(2, 6), while the triangle A'B'C' is at A'(6, -8), B'(8, -4), C'(0, -6).

A transformation is the movement of a point from its initial location to a new location. Types of transformation are rotation, translation, dilation and rotation.

If a point O(x, y) is translated a units on the x axis and b units on the y axis, the new coordinate is O'(x+a, y+b).

If a point O(x, y) is reflected across the x axis, the new coordinate is O'(x, -y)

Hence if triangle ABC is translated -2 units on the x axis (2 units left), the new coordinates are A*(6, 8), B*(8, 4), C*(0, 6). If a reflection across the x axis is then done, the new coordinates are A'(6, -8), B'(8, -4), C'(0, -6).

7 0

2 years ago

Read 2 more answers