Shalise competed in a jigsaw puzzle competition where participants are timed on how long they take to complete puzzles of variou
s sizes.
Shalise completed a small puzzle in 75 minutes and a large jigsaw puzzle in 140 minutes. For all participants, the distribution of completion
time for the small puzzle was approximately normal with mean 60 minutes and standard deviation 15 minutes. The distribution of completion
time for the large puzzle was approximately normal with mean 180 minutes and standard deviation 40 minutes.
Approximately what percent of the participants had finishing times greater than Shalise's for each puzzle?
Shalise completed a small puzzle in 75 minutes and a large jigsaw puzzle in 140 minutes. For all participants, the distribution of completion
time for the small puzzle was approximately normal with mean 60 minutes and standard deviation 15 minutes. The distribution of completion
time for the large puzzle was approximately normal with mean 180 minutes and standard deviation 40 minutes.
Approximately what percent of the participants had finishing times greater than Shalise's for each puzzle?
1 answer:
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Answer:
Malik substituted 60 for y instead of x.
Step-by-step explanation:
According to the given situation the computation of error that Malik make first when solving the equation is shown below:-
First, we will find the value of x
x = 625
Now, we have
we will solve the above equation, to find the value of y
24 - 4y = 10
4y = 24 - 10
4y = 14
So, from the above calculation, the correct option is
Malik substituted 60 for y instead of x.