Answer:
The probability that all three have type B+ blood is 0.001728
Step-by-step explanation:
For each person, there are only two possible outcomes. Either they have type B+ blood, or they do not. The probability of a person having type B+ blood is independent of any other person. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
The probability that a person in the United States has type B+ blood is 12%.
This means that 
Three unrelated people in the United States are selected at random.
This means that 
Find the probability that all three have type B+ blood.
This is P(X = 3).


The probability that all three have type B+ blood is 0.001728
Answer:
The length of the missing piece is 2 ft 3 inches
Step-by-step explanation:
Here in this question, we are interested in calculating the length of the remaining piece of the board given that we have the total length of the board and two other pieces.
Mathematically, the remaining piece length can be calculated by subtracting the lengths of the known pieces
That would be;
10 ft - 4 ft 7 inches - 3 ft 2 inches
In a foot there are 12 inches
Thus
10 ft = 10 * 12 = 120 inches
4 ft 7 inches = 4(12) + 7 = 55 inches
3 ft 2 inches = 3(12) + 2 = 36 + 2 = 38 inches
Thus the length of the remaining piece would now be;
120 -55 -38 = 27 inches
That is same as 24 + 3 inches
24 inches = 2 ft
So 27 inches = 2 ft 3 inches
I believe the answer is 3/8. The whole portion of employees, which is translated as 8/8 is deducted by 5/8, which is the population of male employees.
Answer:
P(A) = 0.2
P(B) = 0.25
P(A&B) = 0.05
P(A|B) = 0.2
P(A|B) = P(A) = 0.2
Step-by-step explanation:
P(A) is the probability that the selected student plays soccer.
Then:

P(B) is the probability that the selected student plays basketball.
Then:

P(A and B) is the probability that the selected student plays soccer and basketball:

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.