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loris [4]
2 years ago
5

For 9-10, Write one equation to show a way to break down each number 24

Mathematics
1 answer:
Sergio039 [100]2 years ago
4 0
USE SOCRACTIC IT WOULD DEFINITELY HELP WITH QUESTIONS LIKE THIS TRY IT I PROMISE
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The average rate of change from x = 0 to x = 15 is about −4.667. How does the average rate of change from x = 0 to x = 20 compar
Amanda [17]
First we calculate the ambio rate from x = 0 to x = 15:
 We have:
 R = ((80-10) / (0-15))
 R = -4.666666667
 We now calculate for the entire interval:
 from x = 0 to x = 20:
 R = ((80-2) / (0-20))
 R = -3.9
 Answer:
 What is the average rate of change over the entire slide?
 R = -3.9
 The average rate of change from x = 0 to x = 15 is about -4.667. How does the average rate change from x = 0 to x = 20 compare to this number?
 The percentage difference is:
 (-3.9 / -4.666666667) * (100) = 83.57142857%
 100-83.57142857 = 16.42857143%
6 0
2 years ago
Solve the equation y′ + 3y = t + e^(−2t).
Leni [432]
Hello,

I am going to remember:

y'+3y=0==>y=C*e^(-3t)

y'=C'*e^(-3t)-3C*e^(-3t)

y'+3y=C'*e^(-3t)-3Ce^(-3t)+3C*e^(-3t)=C'*e^(-3t) = t+e^(-2t)
==>C'=(t+e^(-2t))/e^(-3t)=t*e^(3t)+e^t
==>C=e^t+t*e^(3t) /3-e^(3t)/9

==>y= (e^t+t*e^(3t)/3-e^(3t)/9)*e^(-3t)+D
==>y=e^(-2t)+t/3-1/9+D
==>y=e^(-2t)+t/3+k


4 0
2 years ago
El producto de dos números consecutivos es 552 cuáles son esos números?
lara31 [8.8K]

Answer: 23 y 24 ( ó -23 y -24)

Step-by-step explanation:

Dos números consecutivos se escriben como:

n y (n + 1)

done n es un numero entero.

Entonces "El producto de dos números consecutivos es 552"

Se escribe como:

n*(n + 1) = 552

n^2 + n = 552

n^2 + n - 552 = 0

Tenemos una cuadrática, las posibles soluciones son obtenidas con la formula de Bhaskara.

n = \frac{-1 +- \sqrt{1^2 - 4*1*(-552)} }{2} = \frac{-1 +- 47}{2}

Las dos soluciones son.

n = (-1 - 47)/2 = -48/2 = -24

n = (-1 + 47)/2 = 46/2 = 23

Si tomamos la primer solución, n = -24

Entonces los dos números consecutivos son:

n = -24

(n + 1) = -23

Si n = 23 entonces

n + 1 = 24

Lo cual tiene sentido, por que lo único que cambia son los signos, los cuales se cancelarían en la multiplicación.

7 0
2 years ago
Kayson mixes 300300300 milliliters (\text{mL})(mL)left parenthesis, start text, m, L, end text, right parenthesis of spinach, 20
Georgia [21]

Answer:

Total, T = (300s+200b+42d) mg

Step-by-step explanation:

Given that,

Kayson mixes 300 mL spinach, 200 mL of berries, and 42 mL of dressing to make a salad.

There are s mg of vitamin C per mL of spinach, b mg per mL of berries, and d mg per mL of dressing.

In 300 mL of spinach vitamin C is = (300 s)mg

In 200 mL of berries vitamin C is = (200 b)mg

In 42 mL of salad vitamin C is = (42 d)mg

It means that, total mg of vitamin C is :

Total, T = (300s+200b+42d) mg

Hence, this is the required solution.

4 0
2 years ago
Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a)
Salsk061 [2.6K]

Answer:

a) 1 tsp.

b) 1.5 tsp.

c) 2 tsp.

Step-by-step explanation:

Complete Correct Question

Animals: The label on a bottle of pet vitamins lists dosage guidelines. What dosage would you give to each of these animals? (a) a 18 kg adult dog (b) a 6 kg cat (c) 18 kg pregnant dog

- The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

- The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

- The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

Solution

a) 18 kg adult dog

The dosage listed for adult dog is 1/2 tsp per 9 kg dog weight.

9 kg dog weight = (1/2) tsp

18 kg adult dog = (18/9) × (1/2) = 1 teaspoon.

b) 6 kg cat

The dosage listed for adult cat is 1/4 tsp per 1 kg weight.

1 kg cat = (1/4) tsp

6 kg cat = (6/1) × (1/4) = (6/4) = 1.5 teaspoons.

c) 18 kg pregnant dog

The dosage listed for pregnant dog is 1/2 tsp per 4.5 kg dog weight.

4.5 kg dog weight = (1/2) tsp

18 kg pregnant dog = (18/4.5) × (1/2) = 2 teaspoons.

Hope this Helps!!!

4 0
2 years ago
Read 2 more answers
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