To figure out this problem, let's set up an equation first to make it easier:
702.50 = 5.5x + 70
x = amount charged per hour
702.50 = 5.5x + 70
-70 -70
-----------------------------
632.5 = 5.5x
/5.5 /5.5
--------------------
115 = x
Owen was charged $115 per hour
<h2>
Answer with explanation:</h2><h2>
</h2>
The x% confidence interval interval interprets that we are x% confident that the true population mean falls in it.
Given : The owners of an amusement park computed a 90% confidence interval for the number of patrons with annual passes who visit the park daily.
Then, the correct interpretation of 90% confidence interval of (35, 51) will be that owners of an amusement park are 90% confident that the true population mean of the number of patrons with annual passes who visit the park daily lies in it.
Answer:
The annual multiplier is 0.27 and Annual Percent in decrease is 73%.
Step-by-step explanation:
Given:
Initial Value 
Elapsed time 
Final Value 
We need to find the annual multiplier and annual percent of decrease.
Solution:
Now we know that;
The Final value after n years is equal to Initial value multiplied by the multiplier raise to number of elapsed years.
framing in equation form we get;

m⇒ annual multiplier
Substituting the values we get;

Taking cube root we get;
![\sqrt[3]{m^3}=\sqrt[3]{\frac{1}{50}} \\\\m=0.27](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bm%5E3%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B50%7D%7D%20%20%5C%5C%5C%5Cm%3D0.27)
Hence the annual multiplier is 0.27.
Now We will find the annual percent of decrease.
Now we know that;
annual multiplier is equal to 1 minus the depreciation rate.

r ⇒ annual percent in decrease.

Hence Annual Percent in decrease is 73%.
Answer: 3 hours
Step-by-step explanation: we can make a variable for our answer(x)
Now, we need to find the speed of the boat without the current (y)
we can make this equation: d/t = s: 45/(y + 2.5) = 2 1/4
hence: y = 17.5
now we can substitute in the current's speed: y -2.5
17.5 - 2.5 is 15
now we can solve for x
45/15 = 3
hence, we get 3 hours as our answer