Answer:
D. 1 BB : 2 Bb : 1 bb
Explanation:
This question involves a single gene coding for fur color in guinea pig. Black fur (B) is dominant over white fur (b). This means that, as stated in the question, if a black fur parent (BB) is crossed with a white fur parent (bb), a 100% heterozygous offspring (Bb) with black fur will result.
If two heterozygous guinea pigs are crossed i.e. Bb × Bb, the following gametes will be produced by each heterozygous parent:
Bb = B and b
Using these gametes in a punnet square (see attached image), offsprings with the following genotypic ratio will be produced:
1 BB : 2 Bb : 1 bb
BB and Bb = black fur guinea pigs
bb = white fur guinea pigs
Answer:
d
Explanation:
The answer would be d because limitation of models is basically about non realistic part of models that separate them from real life which is what d is saying.
I believe the answer is C. E. And F.
Make a paraffin block with that wing present inside. Now make fine slices of that block. Take one fine & even slice on a slide & then stain it.
Hope this helps you!
Answer:
Yes.
Explanation:
Yes, Sam regain his vision and seen clearly because the injected gene go to the site where the damaged cell is present which is responsible for vision is replaced by injecting functioning copy of the gene and starts working and the person can see clearly. First the functioning copy of the gene is mutated with Sam's DNA in the cells of his eyes in order to adjust with the gene of eye and then injected so the Sam's DNA can accept the newly mutated gene.
