Using the given formula with v0=56 ft/s and h=40 ft
h = -16t2 + v0t
40 = -16t2 + 56t
16t2 - 56t + 40 = 0
Solving the quadratic equation:
t= (-b+/-(b^2-4ac)^1/2)/2a = (56+/-((-56)^2-4*16*40)^1/2)/2*16 = (56 +/- 24) / 32
We have two possible solutions
t1 = (56+24)/32 = 2.5
t2 = (56-24)/32 = 1
So initially the ball reach a height of 40 ft in 1 second.
Answer:

Explanation:
Thrust is known as a reaction force which appears when a system expels or accelerates mass in one specific direction. If we know the acceleration and the mass of the air expelled by the jet engine, we can compute the thrust
.
The acceleration is calculated by using the dynamics formula

The values are


The thrust is

Answer:
Explanation:
Given
Weight of car 
mass of car 
velocity of car 
radius 
(a)Centripetal acceleration is given by



(b)Force that provide centripetal acceleration



(c)Friction force between car and tires is given by

where
=coefficient of static friction
N=normal reaction
Centripetal force will balance the friction force



The energy transferred to the spring is given by:

where
k is the spring constant
x is the elongation of the spring with respect its initial length
Let's convert the data into the SI units:


so now we can use these data inside the equation ,to find the energy transferred to the spring:
<span>The answer should be the vegitation. </span>