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Tamiku [17]
2 years ago
10

I if the no of Girates at congtin were reduced by 63% what would be the approximate ratio of giraffes to animals in other catego

ry be?​

Mathematics
1 answer:
Arada [10]2 years ago
3 0

Answer:

Giraffe:Others = 3:7

Step-by-step explanation:

<em>See Attachment for complete question</em>

For this question, we only need the data at the Congtin column.

So, we have:

Giraffes = 124

Other = 108

First, we need to reduce Giraffe by 63%.

This gives:

New\ Giraffe = Giraffe - 63\% * Giraffe

New\ Giraffe = 124 - 63\% * 124

New\ Giraffe = 124 - 78.12

New\ Giraffe = 45.88

Represent this as a ratio:

Giraffe:Others = 45.88:108

The closest to this ratio is 3:7.

This is shown by dividing the ratio by 15

i.e.

Giraffe:Others = 45.88/15:108/15

Giraffe:Others = 3.0589:7.2

Approximate:

Giraffe:Others = 3:7

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12x+7&lt;−11 AND5x−8≥4012
Arte-miy333 [17]

Answer:

No solution

Step-by-step explanation:

Given: 12x+7 and  5x-8\geq 40

Solve both inequality separately.

12x+7              Subtraction property of inequality

12x

12x

x

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and

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Please find attachment for number line solution.

No solution

8 0
2 years ago
Read 2 more answers
I will give brainliest to the best answer to this question: Each year, the Department of Water Works measures the chloride conce
Maslowich

Answer:

The total change that will likely occur in 2 years is =-3\frac{2}{3} mg/L        

Step-by-step explanation:

Given : The first year, they found the chloride concentration changed by -1\frac{3}{5} mg/L .

It is estimated that the chloride concentration will change -2\frac{1}{15} mg/L the next year.

To find : What is the total change that will likely occur in 2 years?

Solution :

The chloride concentration changed by -1\frac{3}{5}=-\farc{8}{5} mg/L in first year.

The chloride concentration will change -2\frac{1}{15}=-\frac{31}{15} mg/L the next year.

The total change that will likely occur in 2 years is

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=\frac{-55}{15}

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4 0
2 years ago
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The perimeter of a pool table is about 7.8m. four times the length equals nine times the width. What are the dimensions of the t
Nana76 [90]

The pool's dimension are  l = 2.7 m and w = 1.2 m

Step-by-step explanation:

Step 1 :

Given

The pool's perimeter = 7.8 m

Four times the pool's length = nine times the pool's width.

=> 4l = 9w  => l = (\frac{9}{4}) w

Where l is the pool's length and w is the pool's width

Step 2:

The rectangle's formula for perimeter is 2 (l+w)

Substituting l = (\frac{9}{4}) w ,

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(\frac{13}{2}) w  = 7.8 = > w = 1.2 m

Step 3 :

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Step 4 :

Answer :

The pool's dimension are  l = 2.7 m and w = 1.2 m

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