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lord [1]
2 years ago
10

Caleb’s school is five blocks due north of his home, and the library is two blocks due west of his home. If each city block is a

square with sides measuring 275 feet, which of the following is the closest to the straight-line distance from Caleb’s school to the library?
Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
4 0

Answer:

The closest straight-line distance from Caleb's school to the library is:

  • <u>1480.92 feet</u>

Step-by-step explanation:

Imagine a triangle, where five blocks are a side and two blocks another side, to obtain the closest straight-line distance from Caleb's school to the library you can use the Pythagoras theorem, where the hypotenuse is the closest straight-line:

  • perpendicular^{2} +base^{2} =hypotenuse^{2}

Clearing the hypotenuse is:

  • \sqrt{perpendicular^{2}+base^{2}}= hypotenuse

Now, you only need to identify the distance in each case:

Five blocks = 275 feet * 5 = 1375 feet.

Two blocks = 275 feet * 2 = 550 feet.

At last, you must replace the distances found in the equation cleared:

  • \sqrt{1375 feet^{2}+550 feet^{2}}= hypotenuse
  • <u>Hypotenuse or closest straight-line = 1480.92 feet</u>.

Identifying this, the closest straight-line distance from Caleb's school to the library is <u>1480.92 feet</u>.

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Tim was given a large bag of sweets and ate one third of the sweets before stopping as he was feeling sick. The next day he ate
mars1129 [50]

Answer: In the beginning he was given 27 sweets.

Step-by-step explanation: The most logical thing to do is to solve it backwards, that is, from what he had at the end of the third day up till the beginning of the first day.

On the third day he ate one-third and had 8 sweets left over. To determine how many he started with on the third day, let the total on day three be called a. If one-third of a is eaten, then the left over which is two-thirds is 8. That is;

8/a = 2/3

By cross multiplication we now have

8 x 3 = 2a

24/2 = a

a = 12

Let the number of sweets he had on day two be called b. If he ate one-third of b and he had 12 left over, then the two-thirds left over is 12 and we now have;

12/b = 2/3

By cross multiplication we now have

12 x 3 = 2b

36 = 2b

36/2 = b

b = 18

Let the number of sweets he had on day one be called x. If he ate one-third of x and he had 18 left over, then the two-thirds left over is 18, and we now have;

18/x = 2/3

By cross multiplication we now have

18 x 3 = 2x

54 = 2x

x = 27

Therefore Tim was given 27 sweets at the beginning.

3 0
2 years ago
olivia has a shoebox shaped like a rectangular prism. She decorates 4 faces of the box, leaving the top and bottom without decor
Art [367]

Answer:

440 inches

Step-by-step explanation:

bruh thats too much work

8 0
2 years ago
Read 2 more answers
Robert earned $10, which was 4 less than twice what Eric earned , How much money did Eric earn?
Kisachek [45]

Answer:

Eric's earning is $7

Step-by-step explanation:

Given

Represent Robert's earnings with R and Eric's with E.

R = 10\\R = 2E - 4

Required

What is the value of E?

Substitute 10 for R in the second equation.

10 = 2E - 4

Solve for 2E

2E = 10 + 4

2E = 14

Solve for E

E = 14/2

E = 7

<em>Eric's earning is $7</em>

6 0
2 years ago
Find the point of intersection of the lines: y = 4x + 1 and y = – 2x + 4 A. (2 , 9) B. ( 1 2, 3 ) C. (1 , 2) D. ( 1 4, 2)
alekssr [168]

Answer:

B. (1/2, 3)

Step-by-step explanation:

It is perhaps easiest to try the point values in the equations.

A — 4·2+1 = 9; -2·2 +4 ≠9 . . . . not the answer

B — 4·1/2 +1 = 3; -2·(1/2) +4 = 3 . . . . this is the answer

we need go no further since we have the answer

3 0
2 years ago
Which of the following equations has a maximum at (9,7)
Luba_88 [7]

Answer:

Step-by-step explanation:

Answer:

option C ⇒ C) y = -x² + 18x - 74

Step-by-step explanation:

The given options are:

A) y = -x² + 14x - 40

B) y = -x² - 18x - 88

C) y = -x² + 18x - 74

D) y = -x² - 14x - 58

=================================

The general equation of the parabola has the form:

y = f(x) = ax² + bx + c

The vertex of the parabola has the coordinates (h , k)

where h = \frac{-b}{2a}

and     k = f(h) = f(\frac{-b}{2a})

Check option A: a = -1 , b = 14  ⇒ (h,k) = (7, f(7) ) = (7 , 9)

Check option B: a = -1 , b = -18 ⇒ (h,k) = (-9, f(-9) ) = (-9,-7)

Check option C: a = -1 , b = 18  ⇒ (h,k) = (9, f(9) ) = (9,7)

Check option D: a = -1 , b = -14 ⇒ (h,k) = (-7, f(7) ) = (-7,-9)

So the equation which has a maximum at (9,7) ⇒ y = -x² + 18x - 74

<u>So, the correct answer is option C</u>

6 0
1 year ago
Read 2 more answers
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