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lord [1]
2 years ago
10

Caleb’s school is five blocks due north of his home, and the library is two blocks due west of his home. If each city block is a

square with sides measuring 275 feet, which of the following is the closest to the straight-line distance from Caleb’s school to the library?
Mathematics
1 answer:
Ilia_Sergeevich [38]2 years ago
4 0

Answer:

The closest straight-line distance from Caleb's school to the library is:

  • <u>1480.92 feet</u>

Step-by-step explanation:

Imagine a triangle, where five blocks are a side and two blocks another side, to obtain the closest straight-line distance from Caleb's school to the library you can use the Pythagoras theorem, where the hypotenuse is the closest straight-line:

  • perpendicular^{2} +base^{2} =hypotenuse^{2}

Clearing the hypotenuse is:

  • \sqrt{perpendicular^{2}+base^{2}}= hypotenuse

Now, you only need to identify the distance in each case:

Five blocks = 275 feet * 5 = 1375 feet.

Two blocks = 275 feet * 2 = 550 feet.

At last, you must replace the distances found in the equation cleared:

  • \sqrt{1375 feet^{2}+550 feet^{2}}= hypotenuse
  • <u>Hypotenuse or closest straight-line = 1480.92 feet</u>.

Identifying this, the closest straight-line distance from Caleb's school to the library is <u>1480.92 feet</u>.

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