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arsen [322]
2 years ago
8

A quadratic pattern has a second term equal to 1,a third term equal to -16 and a fifth term equal to -14

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
7 0
Given are several terms in a quadratic pattern:

a1 = ?
a2 = 1
a3 = -16
a4 = ?
a5 = -14

let:

x       y
1       ?
2       1
3      -16
4       ?
5       -14

considering the 2nd term and 3rd term, we can determine a quadratic function:

y = -17x + 35

therefore,

a1 = 18
a4 = -33
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After the bank cashed a check Maureen wrote for $60, her balance was Negative 14 dollars. The equation b + (negative 60) = negat
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B + (-60) = -14
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b = -74

What error, if any, did Maureen make?

Maureen's work is correct, and her original balance was -$74.

Maureen should have added 60 to both sides.

Maureen should have added 14 to both sides.

Maureen made a computational error when she subtracted -14 - 60
Maureen's work is correct, and her original balance was -$74.

--> Maureen should have added 60 to both sides.

Maureen should have added 14 to both sides.

Maureen made a computational error when she subtracted -14 - 60
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Find the percent of discount. Original price: $95 Sale price: $61.75
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1.538 i took the test
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. A 25-ft ladder is leaning against a wall. If we push the ladder toward the wall at a rate of 1 ft/sec, and the bottom of the l
Vlada [557]

Answer:

0.75 feet per second.

Step-by-step explanation:

Please find the attachment.

We have been given that a 25-ft ladder is leaning against a wall. We can see from the attachment that ladder forms a right triangle with respect to wall and ground.

So we can set a Pythagoras theorem as:

x^2+y^2=25^2

x^2+y^2=625

Now, we need to find the derivative of above equation with respect to time.

2x\cdot \frac{dx}{dt}+2y\cdot \frac{dy}{dt}=0

Since the adder is moving toward the wall at a rate of 1 ft/sec for 5 sec, so x after 5 seconds would be: 20-1(5)=20-5=15

Let us solve for y using Pythagoras theorem.

y^2+15^2=25^2

y^2+225=625

y^2=625-225

y^2=400

Take positive square root:

\sqrt{y^2}=\sqrt{400}

y=20

Upon substituting our given values in derivative equation, we will get:

2x\cdot \frac{dx}{dt}+2y\cdot \frac{dy}{dt}=0

2(15)\cdot(-1)+2(20)\cdot \frac{dy}{dt}=0

-30+40\cdot \frac{dy}{dt}=0

40\cdot \frac{dy}{dt}=30

\frac{dy}{dt}=\frac{30}{40}

\frac{dy}{dt}=0.75

Therefore, the ladder is moving up at a rate of 0.75 feet per second.

3 0
2 years ago
Copy and complete each table.
LUCKY_DIMON [66]

Answer:

5th term of sequence = -18

nth term of the sequence = -5n + 7

Step-by-step explanation:

Difference between successive and previous term of the output,

T_{2}-T_{1} = -3 - 2

           = -5

Similarly, T_{3}-T_{2}=-8-(-3)

                            = -5

There is a common difference 'd' = (-5)

Therefore, the sequence formed will be an arithmetic sequence.

First term of the sequence 'a' = 2

Explicit formula of an arithmetic sequence, T_{n} = a + (n - 1)d  [n = input value]

T_{n} = 2 + (n - 1)(-5)

    = 2 - 5n + 5

    = -5n + 7

5th term of this sequence,

T_{5}=2+(5-1)(-5)

    = 2 - 20

    = -18

Therefore, 5th term of sequence = -18

                  nth term of the sequence = -5n + 7

3 0
2 years ago
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