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SVETLANKA909090 [29]
2 years ago
14

Which of the following equations has a maximum at (9,7)

Mathematics
2 answers:
Lelechka [254]2 years ago
7 0

Answer:

C

Step-by-step explanation:

y = a(x - h)² + k

Since it's a maximum turning point:

a < 0

From the options available, a = -1

y = -(x - 9)² + 7

y = -(x² - 18x + 81) + 7

y = -x² + 18x - 81 + 7

y = -x² + 18x - 74

Luba_88 [7]2 years ago
6 0

Answer:

Step-by-step explanation:

Answer:

option C ⇒ C) y = -x² + 18x - 74

Step-by-step explanation:

The given options are:

A) y = -x² + 14x - 40

B) y = -x² - 18x - 88

C) y = -x² + 18x - 74

D) y = -x² - 14x - 58

=================================

The general equation of the parabola has the form:

y = f(x) = ax² + bx + c

The vertex of the parabola has the coordinates (h , k)

where h = \frac{-b}{2a}

and     k = f(h) = f(\frac{-b}{2a})

Check option A: a = -1 , b = 14  ⇒ (h,k) = (7, f(7) ) = (7 , 9)

Check option B: a = -1 , b = -18 ⇒ (h,k) = (-9, f(-9) ) = (-9,-7)

Check option C: a = -1 , b = 18  ⇒ (h,k) = (9, f(9) ) = (9,7)

Check option D: a = -1 , b = -14 ⇒ (h,k) = (-7, f(7) ) = (-7,-9)

So the equation which has a maximum at (9,7) ⇒ y = -x² + 18x - 74

<u>So, the correct answer is option C</u>

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ELEN [110]

The correct answer is (-4)(3)+(-4)(1/4)

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Which function has zeros at x = 10 and x = 2? f(x) = x2 – 12x + 20 f(x) = x2 – 20x + 12 f(x) = 5x2 + 40x + 60 f(x) = 5x2 + 60x +
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Answer:

x^2 -12x+20

Step-by-step explanation:

If the zeros of the functions are at 10 and 2

(x-10) (x-2)

FOIL

x^2 -2x-10x+20

Combine like terms

x^2 -12x+20

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2 years ago
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A teacher decides to purchase a new car and considers two options. Option one is the new Zoomba for $60,000 with an expected dep
kupik [55]

Answer:

She chose Option 2 which is a linear option, because it offers a smaller lose    

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The final value for option 2=$32,800

Step-by-step explanation:

Option 1

New Zoomba for 60000 with a depreciation rat of 2%per month for 3 years

Exponential equation;

y=a(1-r)^t

where;

y=future value

a=initial value=60000

r=depreciation rate=2% per month

t=time interval=12×3=36 months

Replacing;

y=60000(1-2/100)^36

y=60000(0.98)^36=28,992.79

The value after 3 years=$28,992.79

Initial value-Final value=(60000-28992.79)=$31007.21

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(31007.21/60000)×100=51.68%

Option 2

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Linear equation;

y=a-bt

where;

y=Future value

a=Initial value=$40,000

b=the depreciation amount per time interval=$200 per month for 3 years

t=time interval=(3×12)=36 months

Replacing;

y=40000-(200×36)

y=32,800

Final value=y=$32,800

Initial value-Final value=(40000-32800)=$7200

Percentage of initial value lost=((Final value-Initial Value)/(Initial Value))×100

(7200/40000)×100=18%

Option 1(51.68%)>Option 2(18%) therefor Option 1 loses value at a faster rate than Option 2

She chose Option 2 which is a linear option, because it offers a smaller lose    

in value compared to option 1 which is an exponential option

4 0
2 years ago
If n - 2y = 3y- n/m,find the value of n when y = 5 and m = -3
Gnom [1K]

Answer:

37 1/2

Step-by-step explanation:

n - 2y = 3y- n/m,

find the value of n when y = 5 and m = -3

--------

n-2*5=3*5-n/-3

n-10=15+n/3

n-n/3=15+10

2n/3=25

2n=3*25

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Yes, because the slope of the line is closer to 0 than to 1, which indicates a strong association between the variables.

Step-by-step explanation:

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