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1 year ago

Which of the following equations has a maximum at (9,7)

Mathematics

2 answers:

Lelechka [254]1 year ago

7 0

Answer:

Step-by-step explanation:

y = a(x - h)² + k

Since it's a maximum turning point:

a < 0

From the options available, a = -1

y = -(x - 9)² + 7

y = -(x² - 18x + 81) + 7

y = -x² + 18x - 81 + 7

y = -x² + 18x - 74

Luba_88 [7]1 year ago

6 0

Answer:

Step-by-step explanation:

Answer:

option C ⇒ C) y = -x² + 18x - 74

Step-by-step explanation:

The given options are:

A) y = -x² + 14x - 40

B) y = -x² - 18x - 88

C) y = -x² + 18x - 74

D) y = -x² - 14x - 58

=================================

The general equation of the parabola has the form:

y = f(x) = ax² + bx + c

The vertex of the parabola has the coordinates (h , k)

where h = $\frac{-b}{2a}$

and k = f(h) = f( $\frac{-b}{2a}$ )

Check option A: a = -1 , b = 14 ⇒ (h,k) = (7, f(7) ) = (7 , 9)

Check option B: a = -1 , b = -18 ⇒ (h,k) = (-9, f(-9) ) = (-9,-7)

Check option C: a = -1 , b = 18 ⇒ (h,k) = (9, f(9) ) = (9,7)

Check option D: a = -1 , b = -14 ⇒ (h,k) = (-7, f(7) ) = (-7,-9)

So the equation which has a maximum at (9,7) ⇒ y = -x² + 18x - 74

<u>So, the correct answer is option C</u>

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Coupons driving visits. A store randomly samples 603 shoppers over the course of a year and nds that 142 of them made their visi

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Answer:

The 95% confidence interval for the proportion of all shoppers during the year whose visit was because of a coupon they'd received in the mail is (0.2016, 0.2694)

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

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In which

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For this problem, we have that:

$n = 603, \pi = \frac{142}{603} = 0.2355$

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So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 - 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2016$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.2355 + 1.96\sqrt{\frac{0.2355*0.7645}{603}} = 0.2694$

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1 year ago

Amala listed her assets and liabilities. Credit Card Balance Car (Paid in full) Jewelry Student Loan Savings Account Stocks $850

MakcuM [25]

Answer:

Total of Amala’s liabilities is $5500 .

Step-by-step explanation:

Liabilities is defined as the sums of money which it owes .

As given

Amala listed her assets and liabilities. Credit Card Balance Car (Paid in full) Jewelry Student Loan Savings Account Stocks $850 $2,200 $125 $2,500 $1,200 $1,500 .

As Credit card balance , car (Paid in full) and student loan are Amala liabilities .

Thus

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Putting all the values in the above

Total amount of Amala’s liabilities = 850 + 2200 + 2500

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Therefore the total of Amala’s liabilities is $5500 .

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2 years ago

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Answer:

Daniel can read his data and refer to line as best line of fit and estimate an average per set of hours.

Step-by-step explanation:

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1 year ago

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Answer:

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Step-by-step explanation:

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