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OLEGan [10]
2 years ago
9

Missy is constructing a fence that consists of parallel sides line AB and line EF. Complete the proof to explain how she can sho

w that m∠AKL = 116° by filling in the missing justifications. Statement Justification line AB ∥ line EF m∠KLF = 116° Given m∠KLF+ m∠BKL = 180° 1. m∠BKL + m∠AKL = 180° Linear Pair Postulate m∠KLF + m∠BKL = m∠BKL + m∠AKL 2. m∠KLF = m∠AKL Subtraction Property m∠AKL = m∠KLF Symmetric Property m∠AKL = 116° Substitution Property A. 1. Alternate Interior Angles Theorem; 2. Substitution Property B. 1. Definition of Complementary Angles; 2. Substitution Property C. 1. Definition of Supplementary Angles; 2. Transitive Property D. 1. Same-Side Interior Angles Theorem; 2. Transitive Property
Mathematics
1 answer:
kozerog [31]2 years ago
3 0

Answer:

The correct option is;

D. 1. Same-Side Interior Angles Theorem

2. Transitive Property

Step-by-step explanation:

The two column proof is given as follows;

Statement    {}                                            Justification

line AB║line EF   {}                                       Given

m∠KLF = 116°    {}                                          Given

1. m∠KLF + m∠BKL = 180    {}                      <u>1. Same side supplementary angles</u>

2. m∠BKL + m∠AKL = 180°    {}                     Linear pair postulate

3. m∠KLF + m∠BKL = m∠BKL + m∠AKL    {}<u>2. Transitive property</u>

4. m∠KLF = m∠AKL   {}                                  Subtraction property      

5. m∠AKL = m∠KLF  {}                                   Symmetric property

6. m∠AKL = 116°  {}                                         Substitution property.

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vladimir2022 [97]

Answer:

30°

Step-by-step explanation:

Law of Sines = \frac{a}{Sin A} = \frac{b}{Sin B} = \frac{c}{Sin C}

\frac{2}{Sin 30} = \frac{2}{Sin B}

\frac{2}{Sin 30} = \frac{2}{Sin 30}

Therefore, m∠B = 30°

Hope that's right and helps

6 0
2 years ago
Demand for Tablet Computers The quantity demanded per month, x, of a certain make of tablet computer is related to the average u
soldier1979 [14.2K]

x = f ( p ) = \frac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } } \\\\ \qquad { p ( t ) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \quad ( 0 \leq t \leq 60 ) }

Answer:

12.0 tablet computers/month

Step-by-step explanation:

The average price of the tablet 25 months from now will be:

p ( 25) = \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { 25 } } + 200 \\= \dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \times 5 } + 200\\\\=\dfrac { 400 } { 1 + \dfrac { 5 } { 8 } } + 200\\p(25)=\dfrac { 5800 } {13}

Next, we determine the rate at which the quantity demanded changes with respect to time.

Using Chain Rule (and a calculator)

\dfrac{dx}{dt}= \dfrac{dx}{dp}\dfrac{dp}{dt}

\dfrac{dx}{dp}= \dfrac{d}{dp}\left[{ \dfrac { 100 } { 9 } \sqrt { 810,000 - p ^ { 2 } } }\right] =-\dfrac{100}{9}p(810,000-p^2)^{-1/2}

\dfrac{dp}{dt}=\dfrac{d}{dt}\left[\dfrac { 400 } { 1 + \dfrac { 1 } { 8 } \sqrt { t } } + 200 \right]=-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}

Therefore:

\dfrac{dx}{dt}= \left[-\dfrac{100}{9}p(810,000-p^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt { t } \right]^{-2}t^{-1/2}\right]

Recall that at t=25, p(25)=\dfrac { 5800 } {13} \approx 446.15

Therefore:

\dfrac{dx}{dt}(25)= \left[-\dfrac{100}{9}\times 446.15(810,000-446.15^2)^{-1/2}\right]\left[-25\left[1 + \dfrac { 1 } { 8 } \sqrt {25} \right]^{-2}25^{-1/2}\right]\\=12.009

The quantity demanded per month of the tablet computers will be changing at a rate of 12 tablet computers/month correct to 1 decimal place.

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7 0
2 years ago
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Svetradugi [14.3K]

Answer:

200 dollars,

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Step-by-step explanation:

Since her website had 100 subscribers last month, she earned $1000 (100 x 10). This month, 30 members joined and 10 members left, so in total, she gained 20 subscribers for a total of 120 subscribers this month. So she made 1200 dollars this month (100 x 120). She earned 200 more dollars this month since 1200-1000=20.

4 0
2 years ago
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Answer:

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Step-by-step explanation:

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