Question

A student measured the mass of some sodium chloride for a lab. the lab called for 6.25 g (the accurate measurement ) , but the student measured 6.00 g instead . what is the percent error for this mass ? Show your work .

Answer 1

Answer:

The answer is

$\huge 4\%$

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\%$

From the question

actual mass = 6.25 g

error = 6.25 - 6 = 0.25

So we have

$p(\%) = \frac{0.25}{6.25} \times 100$

We have the final answer as

4 %

Hope this helps you