Answer:
A) The probability is 0.95 that the percent of adults living in the United States who are satisfied with their health care plans is between 63.6% and 68.4%.
Step-by-step explanation:
A polling agency reported that 66 percent of adults living in the United States were satisfied with their health care plans. The estimate was taken from a random sample of 1,542 adults living in the United States, and the 95 percent confidence interval for the population proportion was calculated as (0.636, 0.684).
This means that we are 95% sure that the true proportion of adults living in the United States who were satisfied with their health care plans is between 0.636 and 0.684.
So the correct answer is:
A) The probability is 0.95 that the percent of adults living in the United States who are satisfied with their health care plans is between 63.6% and 68.4%.
Answer:
Convert 15
% to a decimal.
Then multiply 0.15 x 13450. That means the answer is $2,017.50
Please mark brainliest if this helped.
X = 96
100 137.4
137.4x=(100)(96)
137.4x=9600
137.4x/137.4=9600/137.4
x=70%
Answer:
(a) 0.932
(b) 0.0653
(c) 0.032
(d) 0.316
(e) 0.251
Step-by-step explanation:
From the table with mean parameter μ = 5, we can compute the following cumulative and density probability
(a) 
(cumulative)
(b) P(X = 8) = 0.0653 (density)
(c) 
(cumulative)
(d) 
(cumulative)
(e) 
