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adoni [48]
1 year ago
15

There are between 60 and 100 children at the sunny side holiday camp. When the children are put into pairs, there is 1 child lef

t. When they are put into groups of 5, there is 1 child left. When they are put into groups of 8, there is 1 child left. How many children are there at the camp ?
Mathematics
1 answer:
Alik [6]1 year ago
8 0

Answer:

2×5×8 = 80

80+1 81

There are 81 students in the camp

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The sum of the series 5(1/2)^i is x/1024 Then x =
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I just got this question. I think the answer is 5.
8 0
2 years ago
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There are two approaches to solving the equation -3x + 10 = 4x - 20 Subtract 4x from both sides. OR Add 3x to both sides. –7x +
Scrat [10]

<u>Answer:</u>

There are two approaches to solving the equation -3x + 10 = 4x - 20. The value of x after solving in both methods is 4.2857.

<u>Solution:</u>

Given, equation is -3x + 10 = 4x – 20.

We have to solve the given equation in two methods, now let us see the first method.

<u><em>1st method ⇒ by subtracting 4x from both sides.</em></u>

Then, -3x + 10 = 4x – 20 ⇒ -3x + 10 – 4x = 4x – 20 – 4x ⇒ -3x – 4x = -20 – 10 ⇒ -7x = -30 ⇒ 7x = 30  

Then, x = \frac{30}{7}

Now, let us use the 2nd method.

<em><u>2nd method ⇒ by adding 3x on both sides.</u></em>

Then, -3x + 10 = 4x – 20 ⇒ -3x + 10 + 3x = 4x – 20 + 3x

⇒ 10 + 20 = 4x + 3x

⇒ 7x = 30

⇒ x = \frac{30}{7}

Hence, the value of x after solving in both methods is \frac{30}{7} = 4.2857.

6 0
2 years ago
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On a coordinate plane, square P Q R S is shown. Point P is at (4, 2), point Q is at (8, 5), point R is at (5, 9), and point S is
sergey [27]

Answer:

(D)The midpoint of both diagonals is (4 and one-half, 5 and one-half), the slope of RP is 7, and the slope of SQ is Negative one-sevenths.

Step-by-step explanation:

  • Point P is at (4, 2),
  • Point Q is at (8, 5),
  • Point R is at (5, 9), and
  • Point S is at (1, 6)

Midpoint of SQ =\frac{1}{2}(1+8,5+6)=(4.5,5.5)

Midpoint of PR =\frac{1}{2}(4+5,2+9)=(4.5,5.5)

Now, we have established that the midpoints (point of bisection) are at the same point.

Two lines are perpendicular if the slope of one is the negative reciprocal of the other.

In option D

  • Slope of RP =7
  • Slope of SQ  =-\dfrac17

Therefore, lines RP and SQ are perpendicular.

Option D is the correct option.

6 0
2 years ago
You have a budget of $48. You want to buy fruit and granola bars. Fruit costs $4 per pound, and the granola bars are $1 each. Yo
zzz [600]

1)Define the variables you will use in your model.

Let

x------->total pounds of the fruit

y-------> the total number of granola bars

TC----> total cost

Tf------> total cost of the fruit

Tg----> total cost of the granola bars

2) Write an inequality representing the total cost of your purchase. (3 points)

a. Each pound of fruit costs $4. Write an expression that shows the total cost of the fruit. Use the variable you identified in question 1

Tf=4*x

b. Each granola bar costs $1. Write an expression that shows the total cost of the granola bars. Use the variable you identified in question 1.

Tg=1*y--------> Tg=y

c. Combine the expressions from parts a and b to write an expression for the total cost. Then use this expression to write an inequality that compares the total cost with the amount you have to spend.

TC=Tf+Tg

TC=4*x+y

inequality-------> 4x+y \leq 48

3. Write the inequality that models the number of granola bars you need to buy.

You need at least 10 granola bars

so

y\geq 10

4. Describe in words what each of your inequalities means

inequality 1

4x+y \leq 48

the total cost of fruits plus the total cost of granola bars must be less than or equal to 48 dollars

inequality 2

y\geq 10

5. Graph your system of inequalities.

using a graph tool

see the attached figure

6. Identify one point on the graph that represents a viable solution to the problem, and then identify one point that does not represent a viable solution.

Let

A-------> one point on the graph that represents a viable solution

B-------> one point on the graph that does not represent a viable solution

A(4,20)

x=4-------> total pounds of the fruit

y=20------> the total number of granola bars

check point A

substitute the values of x and y in the inequality 1

4x+y \leq 48

4*4+20\leq 48\\ 36\leq 48-------> is ok

substitute the values of x and y in the inequality 2

y\geq 10

20\geq 10--------> is ok

the point A represents a viable solution, because satisfies both inequalities

B(10,30)

x=10-------> total pounds of the fruit

y=30------> the total number of granola bars

check point B

substitute the values of x and y in the inequality 1

4x+y \leq 48

4*10+30\leq 48\\ 70\leq 48-------> is not a viable solution

substitute the values of x and y in the inequality 2

y\geq 10

30\geq 10--------> is ok

the point B is not a viable solution because does not satisfy the inequality 1

3 0
1 year ago
a computer shop charges 20 pesos per hour (or a fraction of an hour) for the first two hours and additional 10 pesos per hour fo
Serhud [2]

Answer:

The equation for the price, as a function of time in hours is:

P(x) = 20*x    for 0 ≤ x ≤ 2

P(x) = 40 + 10*(x - 2)  for  2 ≤ x

Now, we want to evaluate this function in 40 mins.

we know that 1 hour = 60mins.

Then 40 mins = (40/60) hours = 0.67 hours.

Then we input this in our function, and because this is smaller than 2, we use the first piece of our function:

P(0.67) = 20*0.67 = 13.4

So in 40 mins, the charge will be 13.4 pesos.

7 0
2 years ago
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