A calculator screen shows a number in scientific notation as 1.04E10. Write this number in standard form.

Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. x2 + y2 = 25 (a) Fin

Artemon [7]

Answer:

(a) $\frac{dy}{dt}=-3\frac{3}{4}$

(b) $\frac{dx}{dt}=3\frac{3}{4}$

Step-by-step explanation:

$x^{2} +y^{2}=25$

Take $\frac{d}{dt}$ of of each term.

$\frac{d}{dt}(x^{2})+\frac{d}{dt}(y^{2})=\frac{d}{dt}(25)\\\\(\frac{d}{dx}(x^{2})*\frac{dx}{dt}) +(\frac{d}{dy}(y^{2})*\frac{dy}{dt})=\frac{d}{dt}(25)\\\\2x\frac{dx}{dt} +2y\frac{dy}{dt} = 0\\\\$

For Question a

$2y\frac{dy}{dt}=-2x\frac{dx}{dt}\\\\\frac{dy}{dt}=\frac{-2x\frac{dx}{dt}}{2y} \\\\\frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}$

Given that x = 3, y = 4, and dx/dt = 5.

$\frac{dy}{dt}=-\frac{3}{4}*5=-\frac{15}{4}\\ \\\frac{dy}{dt}=-3\frac{3}{4}$

For Question b

$2x\frac{dx}{dt}=-2y\frac{dy}{dt}\\\\\frac{dx}{dt}=\frac{-2y\frac{dy}{dt}}{2x} \\\\\frac{dx}{dt}=-\frac{y}{x}\frac{dy}{dt}$

Given that x = 4, y = 3, and dx/dt = -5.

$\frac{dx}{dt}=-\frac{3}{4}*-5=\frac{15}{4}\\ \\\frac{dx}{dt}=3\frac{3}{4}$

5 0

2 years ago

An employee of a grocery store is placing an order for soda. There are 8 varieties of soda and they are sold in cases. Each case

Maksim231197 [3]

Answer:

Hey the answer is e i think

Step-by-step explanation:

3 0

2 years ago

What are the classifications of each system? Drag the answer into the box to match each system. {4x−2y=102x−y=5 {y=2x−3−2x+y=−5

siniylev [52]

The first one is. coincident
second. inconsistent
third. consistent independent

I just did this quiz (:

7 0

2 years ago

Read 2 more answers

6.5% of people in the U.S. Have A- blood type. You randomly select 6 Americans and ask them if their blood type is A-. a) Find t

Keith_Richards [23]

Answer:

a) 7.54189*10^-8

b) 0.99999999

c) E ( X ) = 0.39 , s ( X ) = 0.604

Step-by-step explanation:

Solution:-

- We will assume the proportion of people with A- blood group is independent and remains constant for a fairly small sample of n = 6 Americans selected at random.

- We will denote a random variable X = The number of americans out of 6 that have blood group type A-.

- The random variable is assumed to follow binomial distribution.

- The probability of success is the proportion of people in U.S that have blood group type A-, p = 0.065:

X ~ Bin ( 6 , 0.065 )

Where, r represents the number of americans out of selected 6 have blood group A-. The pmf of a binomial variate is given as:

P ( X = r ) = nCr * ( p ) ^r * ( 1 - p ) ^ ( n - r )

a) Find the probability that all 6 are type A-

- We will pmf given above and set r = 6. And evaluate the resulting probability:

P ( X = 6 ) = 6C6 * ( p )^6 * ( 1 - p ) ^ ( 0 )

= p^6

= ( 0.065 )^6

= 7.54189*10^-8

b) Find the probability that at most 4 of them are type A-

- We will pmf given above and evaluate the following expression:

P ( X ≤ 4 ) = 1 - P ( X = 5 ) - P ( X = 6 )

P ( X ≤ 4 ) = 1 - 6C5 * ( p )^5 * ( 1 - p ) ^ ( 1 ) - p^6

= 1 - 6*(0.065)^5 ( 0.935 ) - 0.065^6

= 1 - 6.50923*10^-8 - 7.54189*10^-8

= 0.99999999

c) Find the mean and standard deviation.

- The mean E ( X ) of the defined random variable distributed binomially is given by:

E ( X ) = n*p = 6*0.065 = 0.39 people

- The mean s( X ) of the defined random variable distributed binomially is given by:

s ( X ) = √n*p*q = √(6*0.065*0.935) = 0.604

5 0

2 years ago

Whitney bought a watch for $107.50. The finance charge was $11 and she paid for it over 6 months.

Anna11 [10]

Answer:

Her proximate APR is 5.1%

Step-by-step explanation:

The formula of the APR is $APR=\frac{FC}{A}$ × $\frac{m}{12}$ × 100%, where

FC is the finance charge
A is the amount financed
m is the number of months

∵ Whitney bought a watch for $107.5

∴ A = 107.5

∵ The finance charge was $11

∴ FC = 11

∵ She paid for it over 6 months

∴ m = 6

- Substitute these values in the formula above

∵ $APR=\frac{11}{107.5}$ × $\frac{6}{12}$ × 100%

∴ APR = 5.11627907%

- Round it to the nearest tenth

∴ APR = 5.1%

Her proximate APR is 5.1%

4 0

2 years ago