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1 year ago

Ella completed the following work to test the equivalence of two expressions.

2 answers:

6 0

Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Step-by-step explanation:

Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.

Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

3f + 2.6 = 3.1 + 2.6 = 3 + 2.6 = 5.6

2f + 2.6 = 2.1 + 2.6 = 2 + 2.6 = 4.6

5.6 = 4.6

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

3f + 2.6 = 2f + 2.6

3f = 2f

3f - 2f = 0

f = 0

This is true only when f=0.

Hence,

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Brrunno [24]1 year ago

5 0

Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Step-by-step explanation:

Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.

Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

This is true only when f=0.

Hence,

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

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A caterer provides a conference banquet for a price of $40 per person for 20 or fewer people but will decrease the price by $1 p

mel-nik [20]

Answer:

The maximum revenue is $900, obtained with 30 people

Step-by-step explanation:

Naturally, the answer should be a number equal or higher than 20, because up to 20 persons, each one pays the same. Lets define a revenue function for x greater than or equal to 20.

f(x) = x*(40-(x-20)) = -x²+60x

Note that f multiplies the number of persons by how much would they pay (here, assuming that there are more than 20).

f is quadratic with negative main coefficient and its maximum value will be reached at the vertex.

The value of the x coordinate of the vertex is -b/2a = -60/-2 = 30

for x = 30, f(x) = 30*(40-(30-20))=30*30=900

So the maximum revenue is $900.

7 0

1 year ago

Which real numbers are zeros of the function? f(x)=2x3−x2−8x+4 Select each correct answer. −2 −1 −12 0 12 1 2

Ede4ka [16]

Answer:

Step-by-step explanation:

Given is a function in x as

$f(x)=2x^3-x^2-8x+4$

We have to find the zeroes of the function

Since this is a cubic function this function has three zeroes.

Let us try to factorise this function by grouping two terms together.

$x^2(2x-1)-4(2x-1)\\= (2x-1)(x^2-4)$

= $(2x-1)(x-2)(x+2)$

Equate each factor to 0 to find zeroes as

$-2,2,\frac{1}{2}$

4 0

1 year ago

Roger bowled 7 games last weekend. His scores are 155, 165, 138, 172, 127, 193 , 142. What is the RANGE of Roger's scores?

Verdich [7]

Answer:

Step-by-step explanation:

In statistics, the formula for RANGE is given as the difference between the Highest and the Lowest value.

In the above values we are given data consisting of the 7 games that Roger bowled.

155, 165, 138, 172, 127, 193 , 142.

Step 1

We arrange from the least to the highest.

127, 138, 142, 155, 165, 172, 193

Step 2

Lowest value = 127

Highest value = 193

Step 3

Range = 193 - 127

= 66

Therefore, the range of Roger's scores is 66

4 0

2 years ago

Jeff brought a bottle of water for $2.He also brought some hot dogs for $3 each.Jeff did not spend more than $14 on the hot dog

Gala2k [10]

The answer would be D because 3h + 2 (water) has to be less than or equal to > 14

8 0

1 year ago

Read 2 more answers

The base b(t)b(t)b, (, t, )of a triangle is decreasing at a rate of 131313 millimeters per minute and the height h(t)h(t)h, (, t

dem82 [27]

Answer:

8.5 square mm per minute

Step-by-step explanation:

A = 1/2bh

A' = (1/2)(b'h +bh') . . . . differentiating with respect to time

A' = (1/2)((-13)(1) +(5)(6)) = (1/2)(17) = 8.5 . . . . mm²/min

The area is increasing at the rate of 8.5 mm²/min.

_____

<em>Numerical solution</em>

Consider the triangle dimensions .01 minutes before and after the time of interest.

before: base = 5 + 0.13 = 5.13 mm; height = 1 - 0.06 = 0.94 mm. area = 2.4111 mm²

after: base = 5 -0.13 = 4.87 mm; height = 1 +.06 = 1.06 mm. area = 2.5811 mm²

Average rate of change in that period is

(2.5811 -2.4111)/0.02 = .17/.02 = 8.5 . . . . mm²/min

_____

<em>Comment on the numbers</em>

Note that we have assumed the base is decreasing at 13 mm/min. Quite often, division bars get lost on Brainly, so we're not sure this isn't 1/3 mm/min. At the assumed rate, the triangle will disappear in 5/13 minutes, about 23.08 seconds, when the base becomes zero. Of course, it only came into existence 1/6 minute (10 seconds) ago, when the height became non-zero.

3 0

1 year ago