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1 year ago

Ella completed the following work to test the equivalence of two expressions.

2 answers:

6 0

Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Step-by-step explanation:

Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.

Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

3f + 2.6 = 3.1 + 2.6 = 3 + 2.6 = 5.6

2f + 2.6 = 2.1 + 2.6 = 2 + 2.6 = 4.6

5.6 = 4.6

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

3f + 2.6 = 2f + 2.6

3f = 2f

3f - 2f = 0

f = 0

This is true only when f=0.

Hence,

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Brrunno [24]1 year ago

5 0

Answer:

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

Step-by-step explanation:

Equivalent algebraic expressions are those expressions which on simplification give the same resulting expression.

Two algebraic expressions are said to be equivalent if their values obtained by substituting any values of the variables are same.

Two expressions 3f+2.6 and 2f+2.6 are not equivalent, because when f=1,

Method of substitution can only help her to decide the expresssions are not equivalent, but if she wants to prove the expressions are equivalent, she must prove it for all values of f.

This is true only when f=0.

Hence,

The expressions are not equivalent because Ella did not know that you can’t use substitution to test for equivalence.

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The number of species n found on islands typically increases with the area of the island A. Suppose that this relationship is su

Crazy boy [7]

Answer:

$n(A) = n_1A^k$

Step-by-step explanation:

Taking into account that the growth rate of the number of species on the island is proportional to the density of species (number of species between area of the island), a model based on a differential equation is proposed:

$\frac{dn}{dA} = k\frac{n}{A}$

This differential equation can be solved by the method of separable variables like this:

$\frac{dn}{n} = k\frac{dA}{A}$ with what you get:

$\int\ {\frac{dn}{n}}\ = k\int\ {\frac{dA}{A}}$

$ln|n| = kln|A|+C$ . Taking exponentials on both sides of the equation:

$e^{ln|n|} = e^{ln|A|^{k}+C}$

$n(A) = e^{C}A^{k}$

how do you have to $n (1) = n_1$ , then

$n(A) = n_1A^k$

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2 years ago

On a certain day, the temperature changed at a rate of 3°F per hour. How long did it take for the change in temperature to be -3

mamaluj [8]

Answer:

I think 11 hours.

Step-by-step explanation:

If I know starting temp such as 0 degrees then I can say that it would take 11 hours as 11*3 = 33. If it is 3 degrees, then it would 3*12 = 36 degrees.

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2 years ago

A scale drawing of a rectangular park is 5 inches wide and 7 inches ong. The actal prake is 280 yards long. What is the area of

Roman55 [17]

Given:

A scale drawing of a rectangular park is 5 inches wide and 7 inches long.

The actual park is 280 yards long.

To find:

The area of the actual park.

Solution:

Length of drawing = 7 inches

Length of actual park = 280 yards

The scale factor is

7 inches : 280 yards

1 inches : 40 yards

The width of the drawing is 5 inches. So, the width of actual part is

$40\times 5=200 yards$

The area of the actual park is

$Area=Length \times width$

$Area=280\times 200$

$Area=56000$

Therefore, the area of the actual park is 56000 sq. yards.

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1 year ago

The heights of 1000 students are approximately normally distributed with a mean of 174.5 centimeters and a standard deviation of

yuradex [85]

A. The mean and standard deviation.

The mean of a sampling distribution is approximately equal to the mean of the population. Given that the mean of the population is equal to 174.5, the mean of the sampling distribution is also this value.

The standard deviation of a sample distribution is equal to,

u(m) = u/sqrt n

Substituting the known values,

u(m) = 6.9 / sqrt 25 = 1.38

b. Get the z-score of both items,

z-score = (data point - mean) / standard deviation

z-score of 172.5
z-score = (172.5 - 174.5) / 1.38 = -1.49
This translates to 0.068.

z-score of 175.8
z-score = (175.8 - 174.5) / 1.38 = 0.94
This translates to 0.83.

The difference between the two z-scores is 0.762.

The number of samples with this height is 0.762(200) which is equal to approximately 152.

c. z-score of 172 centimeters

z-score = (172 - 174.5) / 1.38

z-score = -1.81
This translates to 0.03.

The number of people with this height from the sample is (0.03)(200) = 6

8 0

1 year ago

I need to increase my sales by 35% in order to meet my goal for the month. you have 45 Sales and need?

Anastasy [175]

45 + 0.35(45)
We can make it simpler:
1.35(45)
60.75
We can round up to 61
He needs about 16 more sales

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1 year ago

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