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vodomira [7]
2 years ago
15

Data were collected on two variables, x and y, to create a model to predict y from x. A scatterplot of the collected data reveal

ed a curved pattern with a possible cubic relationship (y=ax^3, where a is a constant) between the variables. Which of the following transformations would be most appropriate for creating linearity between the variables?
A - Taking the cube of y
B - Taking the cube root of y
C - Taking the cube root of both y and x
D - Taking the log of y
E - Taking the log of both y and x
Mathematics
1 answer:
Sidana [21]2 years ago
4 0

Answer:

B - Taking the cube root of y

Step-by-step explanation:

Data provided in the question

y = ax^3

Based on the above information

Now we take the cube root of y

So, it would be calculated below:

y1/3 = a1/3 × x

So

As it can seen by the above equation there is a linear relationship between the cube root of y and x

Therefore, the correct option is B.

Hence, all the other options are wrong

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“there are several approximations used for pi, including 3.14 and 22/7. pi is approximately 3.14159265358979..." a. label pi and
BlackZzzverrR [31]
Hello,

a) | |PA|-π |>| |PB|-π | (see pic)

c) 3.14< x/113 <=π <22/7

==>3.14*113<x<22/7 * 113
==>354.82 <x < 355.14285
==>x=355


Answer 355/113=3,1415929203539823008849557522124



6 0
2 years ago
HELP!!
Liono4ka [1.6K]

Answer:

Part 1: The polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2: The vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

Step-by-step explanation:

Part 1:

The vertices of the polygon ABCDE are A(2, 8), B(4, 12), C(10, 12), D(8, 8), and E(6, 6).

The vertices of the polygon MNOPQ are M(-2, 8), N(-4, 12), O(-10, 12), P(-8, 8), and Q(-6, 6).

We need to find the transformation or sequence of transformations that can be performed on polygon ABCDE to show that it is congruent to polygon MNOPQ.

The relation between the vertices of ABCDE and MNOPQ are defined as

(x,y)\rightarrow (-x,y)

It means the polygon ABCDE reflected across y-axis to get the polygon MNOPQ. So, the polygon ABCDE congruent to polygon MNOPQ.

Part 2:

If polygon MNOPQ is translated 3 units right and 5 units down, then

(x,y)\rightarrow (x+3,y-5)

M(-2,8)\rightarrow V(-2+3,8-5)=V(1,3)

N(-4,12)\rightarrow W(-4+3,12-5)=W(-1,7)

O(-10,12)\rightarrow X(-10+3,12-5)=X(-7,7)

P(-8,8)\rightarrow Y(-8+3,8-5)=Y(-5,3)

Q(-6,6)\rightarrow Z(-6+3,6-5)=Z(-3,1)

Therefore the vertices of polygon VWXYZ are V(1, 3), W(-1, 7), X(-7, 7), Y(-5, 3), and Z(-3, 1).

6 0
2 years ago
A square with side length c has an area of 81 square centimeters. The following equation shows the area of the square. c^2 = 81.
kramer

Answer:

9 cm

Step-by-step explanation:

c^2=81

Take the square root of both sides.

The square root of c^2 is c.

The square root of 81 is 9.

c=9

8 0
2 years ago
Read 2 more answers
Jane likes to exercise daily. The table shows the number of calories y she burns by exercising steadily for x minutes. How many
Nataly_w [17]
Do you have a picture of the table?
8 0
2 years ago
Read 2 more answers
The gas tank of a car is filled with a nozzle that discharges gasoline at a constant flow rate. Based on unit considerations of
Cloud [144]

Answer:

It is going 84.12s = 1 minute and 24.12 seconds to fill the tank.

Step-by-step explanation:

The filling time of a gas tank can be given by a first order function in this format:

F(t) = V - r*t

In which F(t) is the current amount of fuel in the tank(in L), V is the volume of the tank(in L), r is the discharge rate of the tank(in L/s) and t is the time in seconds.

Finding the values of the parameters:

The tank is completly empty, so F(t) = 0.

The volume of the tank is 14 gallons. However, the problem states that the volume of the tank is measured in liters.

Each gallon has 3.78L.

So V = 14*3.78 = 53L

The discharge rate for the gas is 38.0 l/min. However, the problem states that the discharge rate is in L/s. So, to find the value of r, we solve the following rule of three.

38 L - 60s

r L - 1s

60r = 38

r = \frac{38}{60}

r = 0.63

Solving the equation:

F(t) = V - r*t

0 = 53 - 0.63t

0.63t = 53

t = \frac{53}{0.63}

t = 84.12s

It is going 84.12s = 1 minute and 24.12 seconds to fill the tank.

6 0
2 years ago
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