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vodomira [7]
2 years ago
15

Data were collected on two variables, x and y, to create a model to predict y from x. A scatterplot of the collected data reveal

ed a curved pattern with a possible cubic relationship (y=ax^3, where a is a constant) between the variables. Which of the following transformations would be most appropriate for creating linearity between the variables?
A - Taking the cube of y
B - Taking the cube root of y
C - Taking the cube root of both y and x
D - Taking the log of y
E - Taking the log of both y and x
Mathematics
1 answer:
Sidana [21]2 years ago
4 0

Answer:

B - Taking the cube root of y

Step-by-step explanation:

Data provided in the question

y = ax^3

Based on the above information

Now we take the cube root of y

So, it would be calculated below:

y1/3 = a1/3 × x

So

As it can seen by the above equation there is a linear relationship between the cube root of y and x

Therefore, the correct option is B.

Hence, all the other options are wrong

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What are the x-intercepts of the function f(x) = –2x2 – 3x + 20?
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The root sof this quadratic equation are -4 and 2.5.


The roots of any quadratic can be found by using the quadratic equation. The equation is below for you.


\frac{-b +/- \sqrt{b^{2}- 4ac}}{2a}


In this equation you use the number attached to x^2 as the a, which in this case is -2. The number attached to x as b, which is in this case -3. And the number at the end as c, which is 20. From there you solve for the answers.


\frac{3 +/- \sqrt{-3^{2}- 4(-2)(20)}}{2(-2)}

\frac{3 +/- \sqrt{9 + 160}}{-4}

\frac{3 +/- 13}}{4}


Now you separate and get the two separate answers. First the positive.


\frac{3 + 13}}{4}

\frac{16}}{4}

4


Now the negative


\frac{3 - 13}}{4}

\frac{-10}}{4}

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5 0
2 years ago
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A has the coordinates (–4, 3) and B has the coordinates (4, 4). If DO,1/2(x, y) is a dilation of △ABC, what is true about the im
fomenos
A dilation is a transformation D_{o,k}(x,y), with center O and a scale factor of k that is not zero, that maps O to itself and any other point P to P'. The center O is a fixed point, P' is the image of P, points O, P and P' are on the same line.

In a dilation of D_{o, \frac{1}{2} }(x,y), the scale factor, \frac{1}{2} is mapping the original figure to the image in such a way that the distances from O to the vertices of the image are half the distances from O to the original figure. Also the size of the image is half the size of the original figure.

Therefore, <span>If D_{o, \frac{1}{2} }(x,y) is a dilation of △ABC, the truth about the image △A'B'C'</span> are:

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*I hope this helped!
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