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yanalaym [24]
2 years ago
14

Katarina wrote the standard form of a linear equation as 4x – 4 x minus StartFraction 2 Over 3 EndFraction y equals 8.Y = 8. Sof

iya told her that the equation was not yet in standard form and gave her the right advice for how to fix it. What advice did Sofiya give to Katarina? Multiply both sides of the equation by 3. The standard form of the equation is 12x – 2y = 24. Multiply both sides of the equation by 3 and then divide both sides by 2. The standard form of the equation is 6x – y = 12. Multiply both sides of the equation by 3. The standard form of the equation is 12x – 2y = 8. Multiply both sides of the equation by 3 and then divide both sides by 2. The standard form of the equation is 6x – y = 4.
Mathematics
2 answers:
Dmitry_Shevchenko [17]2 years ago
7 0

Answer:

B) Multiply both sides of the equation by 3 and then divide both sides by 2. The standard form of the equation is 6x – y = 12.

Step-by-step explanation:

edg2020

Vedmedyk [2.9K]2 years ago
6 0

Answer:

Multiply both sides of the equation by 3 and then divide both sides by 2. The standard form of the equation is 6x – y = 12.

Step-by-step explanation:

Katarina's equation

4x - 2/3y = 8

In order to convert Katrina's linear equation into standard form,

She should find the least common denominator

4x - 2/3y = 8

{4x(3) - 2y(1)} / 3 = 8

(12x - 2y) / 3 = 8

Multiply both sides by 3

(12x - 2y) / 3 × 3 = 8 × 3

12x - 2y = 24

Divide both sides by 2

(12x - 2y) / 2 = 24 / 2

6x - y = 12

The advice sofiya gave Katrina is to Multiply both sides of the equation by 3 and then divide both sides by 2. The standard form of the equation is 6x – y = 12.

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Nancy was laid off and applied for unemployment benefits in July. In her state, the weekly unemployment benefit is 55% of the ​2
tankabanditka [31]

Answer:

$277.91

Step-by-step explanation:

"The ​26-week average of the two highest salaried quarters of the year leading to her application" would be the average of $13,500 and $12,775, or

$13,500 + $12,775

---------------------------- = $13137.50

            2

Dividing this by 26 weeks (equivalent to 6 months), we get $505.29.

Nancy's weekly employment benefit would be 55% of that, or $277.91.

8 0
2 years ago
Elon sat on the dock with his fishing rod, when suddenly he felt the rod being pulled down! He reeled in his
prohojiy [21]

Answer:

The graph is attached.

Step-by-step explanation:

The exercise says that Elon took 35 seconds to pull the boot up to the surface, how the constant rate is:

  • Constant rate: 0.1 meters per second.

To know the meters below the surface that is the boot, we multiply the constant rate by the time Elon took to pull up it:

  • Boot depth = 0.1 m/s *35 s
  • Boot depth = 3.5 meters.

How the boot is pulling up through the time, the formula must subtract the time from the depth, how is below:

  • <u>a = 3.5 - 0.1t</u>

Where:

<em>a = depth.</em>

<em>t = time.</em>

8 0
2 years ago
Jane is taking two courses. The probablity she passes the first course is 0,7. The probablity she passes the second course is 0.
makkiz [27]

Answer:

a. 0.6

b. not independent

c. 0.1

d. 0.4

e. 0.3

Step-by-step explanation:

a.

P(passing first course)=P(C1)=0.7

P(passing second course)=P(C2)=0.8

P(passing at least one course)=P(C1∪C2)=0.9

P( passes both courses)=P(C1∩C2)=?

We know that

P(A∪B)=P(A)+P(B)-P(A∩B)

P(A∩B)=P(A)+P(B)-P(A∪B)

So,

P( passes both courses)=P(C1∩C2)=P(C1)+P(C2)-P(C1∪C2)

P( passes both courses)=P(C1∩C2)=0.7+0.8-0.9

P( passes both courses)=P(C1∩C2)=0.6

Thus, the probability she passes both courses is 0.6.

b.

The event of passing one course is independent of passing another course if

P(C1∩C2)=P(C1)*P(C2)

P(C1)*P(C2)=0.7*0.8=0.56

P(C1∩C2)=0.6

As,

0.6≠0.56

P(C1∩C2)≠P(C1)*P(C2),

So, the event of passing one course is dependent of passing another course.

c.

P(not passing either course)=P(C1∪C2)'=1-P(C1∪C2)

P(not passing either course)=P(C1∪C2)'=1-0.9

P(not passing either course)=P(C1∪C2)'=0.1

Thus, the probability of not passing either course is 0.1.

d.

P(not passing both courses)=P(C1∩C2)'=1-P(C1∩C2)

P(not passing both courses)=P(C1∩C2)'=1-0.6

P(not passing both courses)=P(C1∩C2)'=0.4

Thus, the probability of not passing both courses is 0.4.

e.

P(passing exactly one course)=?

P(passing exactly course 1)=P(C1)-P(C1∩C2)=0.7-0.6=0.1

P(passing exactly course 2)=P(C2)-P(C1∩C2)=0.8-0.6=0.2

P(passing exactly one course)=P(passing exactly course 1)+P(passing exactly course 2)

P(passing exactly one course)=0.1+0.2

P(passing exactly one course)=0.3

Thus, the probability of passing exactly one course is 0.3.

3 0
2 years ago
Carey is trying to decide between two guitars. The first had an original price of $160, but is on sale for $100. The second had
dexar [7]
The second guitar is the answer because it has a lower amount than the first but not by alot
8 0
2 years ago
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1. WHEELS Zack is designing wheels for a concept car.
mars1129 [50]

Answer:

9 inches

Step-by-step explanation:

Diameter=D

Radius=R

D=(2)R

(18)=(2)R

18/2=2/2 R

9=R

4 0
2 years ago
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