Given that,
Depth of seawater, h = 11,033 m
Density seawater, p (rho) = 1025 kg/m³
Gauge Pressure , P = ??
Since, we know that:
Pressure, P = pgh
Pressure = 1025 * 9.81 * 11033
Pressure = 1109395723.3 N/m²
or
Pressure = 1.1 x 10∧8 Pascal
Answer:
v=8m/s
Explanation:
To solve this problem we have to take into account, that the work done by the friction force, after the collision must equal the kinetic energy of both two cars just after the collision. Hence we have
![W_{f}=E_{k}\\W_{f}=\mu N=\mu(m_1+m_1)g\\E_{k}=\frac{1}{2}[m_1+m_2]v^2](https://tex.z-dn.net/?f=W_%7Bf%7D%3DE_%7Bk%7D%5C%5CW_%7Bf%7D%3D%5Cmu%20N%3D%5Cmu%28m_1%2Bm_1%29g%5C%5CE_%7Bk%7D%3D%5Cfrac%7B1%7D%7B2%7D%5Bm_1%2Bm_2%5Dv%5E2)
where
mu: coefficient of kinetic friction
g: gravitational acceleration
We can calculate the speed of the cars after the collision by using

Now , we can compute the speed of the second car by taking into account the conservation of the momentum

the car did not exceed the speed limit
Hope this helps!!
Answer:
The reading of Y is -10°.
Explanation:
For scale X, the ice point is 40° and steam point is 120°.
Difference between the two extremes for scales X = 120 - 40 = 80
For scale X, the ice point and steam points are -30° and 130° respectively.
Difference between the two extremes for scales X = 130 - (-30) = 160
Comparing both scales:
One unit of scale X = x
One unit of scale Y = y
Scale X has 80 divisions while scale Y has 160
80x = 160y
x = 2y
50° in scale X = 10x + ice point in X scale
10 divisions in Y scale = 20y
Reading of Y scale = ice point of Y + 20y
= -30° + 20°
= -10°
"Apparent magnitude" means how bright a star looks to
a person on Earth.
-- The star that appears brightest is the one with the
lowest-number apparent magnitude . . . Star-C, at -4 .
-- All of them are visible from Earth, but may require some 'help'.
The dimmest stars visible with good human eyes under dark,
non-polluted skies are those with apparent magnitude around 6.
Stars B and C would be visible to the unaided eye, but Star-A
would require binoculars.
Around here, a few miles outside of the Chicago city limits, we're
lucky to see Magnitude-4 without binoculars.
-- It's not possible to determine which star has the highest luminosity.
The apparent magnitude depends on the star's distance from Earth
as well as its luminosity.
A flashlight 3 feet from your face appears much brighter than any
star, although any star is more luminous than the flashlight.
Distance from you has a lot to do with it.
_____________________________________________
"Absolute magnitude" means how bright each star would appear
to a person on Earth if all stars were at the same distance from us.
(The distance happens to be 32.6 light years.) It only depends on
the star's real luminosity, not on its distance.
-- It's not possible to determine which star appears brightest.
Star-C (absolute -7) would appear brightest if all stars were
equal distances from us. But a flashlight ... which has a huge-
number absolute magnitude because we couldn't see at all from
32.6 light years away ... can appear very bright from 3 feet in
front of your face.
-- They're all visible from Earth, but a star with absolute magnitude
greater than 6 would need binoculars (or better) to be visible.
-- Yes, if you know a star's absolute magnitude, then you know its
luminosity. The lowest-number absolute magnitudes are the ones
that would appear brightest if all stars were the same distance from
us, so they're the stars with the greatest luminosity. From this group,
that's Star-C.
First we will find the speed of the ball just before it will hit the floor
so in order to find the speed of the cart we will first use energy conservation



So by solving above equation we will have

now in order to find the momentum we can use


