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meriva
2 years ago
12

Siska hit a golf ball into the air with an initial velocity of 56 feet per second. The height h in feet of the ball above the gr

ound can be modeled by h=-16t^{2}+56t, where t is the time in seconds after Sisika hit the ball. Find the time it takes the ball to reach 49 feet above the ground.
Physics
2 answers:
olasank [31]2 years ago
4 0
To find the time it takes for the ball to reach the given height, we need an equation that relates the height and time it travel which is given to be <span>h=-16t^{2}+56t. We just substitute the height of 49 feet then solve for t. We do as follows:

</span><span>h=-16t^{2}+56t
49 = </span>-16t^{2}+56t
t = 1.75 seconds

Hope this answers the question. Have a nice day.
Arte-miy333 [17]2 years ago
3 0

Answer: t=1.75secs

Explanation: The hieght h is related to the time by the given equation

h = -16t² + 56t

Swapping the equation left to right the sign changes

16t² - 56t =-h

But h = 49ft

16t² -56t = -49

Taking -49 to the other side of the equation and equating everything to 0 we have

16t² - 56t + 49 = 0

This is a quadratic equation

Where a=16 , b=-56 and c = 49

t = {- b +or- √{b² - 4*a*c} }/2*a

Substituting in the values correctly we would be left with

t = 56/2*a

= 56/32 =1.75sec

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The environment affects people, but people don't affect the environment.<br><br><br>TRUE OR FALSE
Drupady [299]

Answer: False

Explanation:

The statement that the environment affects people, but people don't affect the environment is incorrect. It should be noted that people also affect the environment.

Some of our impact on the environment include pollution, deforestation, overpopulation, burning of fossil fuels etc. Thus has resulted in changes such as erosion, climate change, etc.

5 0
2 years ago
A 50-kg person stands 1.5 m away from one end of a uniform 6.0-m-long scaffold of mass 70.0 kg.
babymother [125]

Answer

given,

mass of the person, m = 50 Kg

length of scaffold = 6 m

mass of scaffold, M= 70 Kg

distance of person standing from one end = 1.5 m

Tension in the vertical rope = ?

now equating all the vertical forces acting in the system.

T₁ + T₂ = m g + M g

T₁ + T₂ = 50 x 9.8  + 70 x 9.8

T₁ + T₂ = 1176...........(1)

system is equilibrium so, the moment along the system will also be zero.

taking moment about rope with tension T₂.

now,

T₁ x 6 - mg x (6-1.5) - M g x 3 = 0

'3 m' is used because the weight of the scaffold pass through center of gravity.

6 T₁ = 50 x 9.8 x 4.5 + 70 x 9.8 x 3

6 T₁ = 4263

    T₁ = 710.5 N

from equation (1)

T₂ = 1176 - 710.5

 T₂ = 465.5 N

hence, T₁ = 710.5 N and T₂ = 465.5 N

4 0
2 years ago
During the construction of an office building, a hammer is accidentally dropped from a height of 784 ft. the distance (in feet)
Serga [27]
T= 24.5 feet per second. That is the velocity it reaches at the end of its fall
7 0
2 years ago
Read 2 more answers
You buy a AA battery in the store, and it is marked 1.5 V. If this marking is strictly accurate, while this battery is fresh its
vitfil [10]

Answer:

Option A is correct.

when it is used in a circuit. its terminal voltage will be less than 1.5 V.

Explanation:

The terminal voltage of the battery when it is in use in circuits drops lower than the 1.5 V rating given to it due to internal resistance.

All batteries give internal resistances when used in circuits. The internal resistance (though very small) is usually modelled as connected in series with the battery. It is due to some form of interference from the chemical makeup of the battery.

Normally, while the battery is fresh, the voltage (V) obtained at its terminals when connected in series with a resistor of resistance R is V = IR; where I is the current flowing in this circuit.

But once the interenal resistance (r) of the battery comes into play,

V = I₁ (r + R)

The current in the circuit evidently drops (that is I₁ < I) and V = (I₁r + I₁R)

The voltage across the terminals of the battery is no longer V but is now (V) × [R/(R+r)] which is less than the initial V and it reduces as the internal resistance, r, increases.

Hope this Helps!!!

3 0
2 years ago
A 5 kg object near Earth's surface is released from rest such that it falls a distance of 10 m. After the object falls 10 m, it
makkiz [27]

Answer:D

Explanation:

Given

mass of object m=5 kg

Distance traveled h=10 m

velocity acquired v=12 m/s

conserving Energy at the moment when object start falling and when it gains 12 m/s velocity

Initial Energy=mgh=5\times 9.8\times 10=490 J

Final Energy=\frac{1}{2}mv^2+W_{f}

=\frac{1}{2}\cdot 5\cdot 12^2+W_{f}

where W_{f} is friction work if any

490=360+W_{f}

W_{f}=130 J

Since Friction is Present therefore it is a case of Open system and net external Force is zero

An open system is a system where exchange of energy and mass is allowed and Friction is acting on the object shows that system is Open .

4 0
2 years ago
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