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Arte-miy333 [17]
2 years ago
5

Which of the following gives a valid reason for using the given solution method to solve the system of equations shown? Equation

I: 4x − 5y = 4 Equation II: 2x + 3y = 2 Group of answer choices Substitution; equation II can be solved for x in one step by subtracting 3y from both sides. Substitution; equation I can be solved for x in one step by dividing both sides by 4. Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II. Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.
Mathematics
1 answer:
alukav5142 [94]2 years ago
4 0

Answer:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

Step-by-step explanation:

Equation I: 4x − 5y = 4

Equation II: 2x + 3y = 2

These equation can only be solved by Elimination method

Where to Eliminate x :

We Multiply Equation I by a coefficient of x in Equation II and Equation II by the coefficient of x in Equation I

Hence:

Equation I: 4x − 5y = 4 × 2

Equation II: 2x + 3y = 2 × 4

8x - 10y = 20

8x +12y = 6

Therefore, the valid reason using the given solution method to solve the system of equations shown is:

* Elimination; a coefficient in Equation I is an integer multiple of a coefficient in Equation II.

* Elimination; a coefficient in Equation II is an integer multiple of a coefficient in Equation I.

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The number of flaws in a fiber optic cable follows a Poisson distribution. It is known that the mean number of flaws in 50m of c
boyakko [2]

Answer:

(a) The probability of exactly three flaws in 150 m of cable is 0.21246

(b) The probability of at least two flaws in 100m of cable is 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is 0.13063

Step-by-step explanation:

A random variable X has a Poisson distribution and it is referred to as Poisson random variable if and only if its probability distribution is given by

p(x;\lambda)=\frac{\lambda e^{-\lambda}}{x!} for x = 0, 1, 2, ...

where \lambda, the mean number of successes.

(a) To find the probability of exactly three flaws in 150 m of cable, we first need to find the mean number of flaws in 150 m, we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 150 m of cable is 1.2 \cdot 3 =3.6

The probability of exactly three flaws in 150 m of cable is

P(X=3)=p(3;3.6)=\frac{3.6^3e^{-3.6}}{3!} \approx 0.21246

(b) The probability of at least two flaws in 100m of cable is,

we know that the mean number of flaws in 50 m of cable is 1.2, so the mean number of flaws in 100 m of cable is 1.2 \cdot 2 =2.4

P(X\geq 2)=1-P(X

P(X\geq 2)=1-p(0;2.4)-p(1;2.4)\\\\P(X\geq 2)=1-\frac{2.4^0e^{-2.4}}{0!}-\frac{2.4^1e^{-2.4}}{1!}\\\\P(X\geq 2)\approx 0.69155

(c) The probability of exactly one flaw in the first 50 m of cable, and exactly one flaw in the second 50 m of cable is

P(X=1)=p(1;1.2)=\frac{1.2^1e^{-1.2}}{1!}\\P(X=1)\approx 0.36143

The occurrence of flaws in the first and second 50 m of cable are independent events. Therefore the probability of exactly one flaw in the first 50 m and exactly one flaw in the second 50 m is

(0.36143)(0.36143) = 0.13063

4 0
2 years ago
Someone know this please help geometry if you are good at it
polet [3.4K]

Answer:

Option A) outside

----------

hope it helps..

have a great day!!!

3 0
1 year ago
Select the expressions that are equivalent to 18m - 12.
krok68 [10]

Answer:

All the expressions other than option E, is equivalent to the expression 18m - 12.

Step-by-step explanation:

A. 6m - 4 + 6m -4 + 6m - 4

or 6m+6m+6m -4 -4 -4

or 18m -12

B. 12m + 6 - 6m -6

or 12m - 6m + 6 - 6

or 6m

C.6(3m - 2)

or 18m - 12

D.3(6m - 4)

or 18m - 12

E. 24n - 4² + 8 -6m

This option can not satisfy the given expression as it contains another variable as n.

4 0
2 years ago
At the beginning of the business day, a bank's vault held $575,900. By the end of the day, $(3.5 103) had been added to the vaul
Likurg_2 [28]

3.5*10^3=3,500

3,500+ 575,900=579,400

5 0
2 years ago
Which expressions are equivalent to 4^{-2} \cdot 7^{-2}4 −2 ⋅7 −2 4, start superscript, minus, 2, end superscript, dot, 7, start
PolarNik [594]

Answer:

Step-by-step explanation:

Given the expression 4^{-2}•7^{-2}. The following expression are equivalent to given expression on simplification.

Generally from indices, a^-b = 1/a^b. Applying this to the given expression we have:

4^{-2}•7^{-2} = 1/4^2 • 1/7^2

= 1/(4×4) • 1/(7×7)

= 1/16 • 1/49

= 1/(16×49)

= 1/784

4 0
2 years ago
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