Which table has a constant of proportionality between yyy and xxx of \dfrac{1}{6}

If it takes 10 seconds for 10 printers to print out 10 pages of paper, how many seconds will it take 50 printers to print out 50

Fed [463]

Lets use the formula $RWT=J$ to solve this, where,

R is the rate
W is the number of workers/things
T is time
J is number of jobs/things

"If it takes 10 seconds for 10 printers to print out 10 pages of paper" - here -

W is 10 printers, T is 10 seconds, and J is 10 pages. We can write:

$R(10)(10)=10\\R(100)=10\\R=\frac{10}{100}\\R=0.1$

"how many seconds will it take 50 printers to print out 50 pages of paper" - here we use $R=0.1$ (previously found) to figure out T.

$RWT=J\\(0.1)(50)T=50\\5T=50\\T=\frac{50}{5}\\T=10$

So it will take 10 seconds for 50 printers to print 50 pages.

ANSWER: 10 seconds

4 0

2 years ago

Read 2 more answers

A King in ancient times agreed to reward the inventor of chess with one grain of wheat on the first of the 64 squares of a chess

statuscvo [17]

Let's start by visualising this concept.

Number of grains on square:
1 2 4 8 16 ...

We can see that it starts to form a geometric sequence, with the common ratio being 2.

For the first question, we simply want the fifteenth term, so we just use the nth term geometric form:
$T_n = ar^{n - 1}$
$T_{15} = 2^{14} = 16384$

Thus, there are 16, 384 grains on the fifteenth square.

The second question begs the same process, only this time, it's a summation. Using our sum to n terms of geometric sequence, we get:
$S_n = \frac{a(r^{n} - 1)}{r - 1}$
$S_{15} = \frac{2^{15} - 1}{2 - 1}$
$S_{15} = 2^{15} - 1 = 32767$

Thus, there are 32, 767 total grains on the first 15 squares, and you should be able to work the rest from here.

6 0

2 years ago

Read 2 more answers

What is the x-intercept of the line with the equation -2x+1/2y=18

Mkey [24]

The x-intercept is a point on the x-axis.
y=0 at every point on the x-axis.

-2x + 1/2(0) = 18

-2x = 18

Divide each side by -2 : x = -9

7 0

2 years ago

Eve’s teacher asked her to graph the function y=-cot(x)-1 by reflecting the graph of the function y=cot(x) about the x-axis and

Ronch [10]

Answer:

The correct answer is A: Yes, it matters. The graph of a function y = cot(x) should be reflected about the x-axis before it is translated 1 unit up.

Step-by-step explanation:

The reason being is that when there are two factors that affect a graph's verticality, order does matter. Here is the exact reasoning:

Say you translated 1 unit down first. You would then have y = cot(x) - 1. Then, in order to reflect it about the x axis, you must multiply the entire right side of the equation by negative 1. So now you have y = -1(cot(x) -1), which, when distributed, gives you: y = -cot(x) + 1, instead of y = -cot(x) -1. Therefore, you must reflect before you translate.

And you may be wondering, why then, isn't D correct? Since, you could fix that by translating up 1 and then reflecting, so that you get the final product. Well, it specifies that it can be done in any order. So one way you could get the equation you want, but the other way, you get y = -cot(x) + 1, which, again, is incorrect.

I hope this cleared it up for you!

5 0

2 years ago

Read 2 more answers

It takes 5 carpenters 5 hours to make 5 chairs. How long would it take 100 carpenters to make 100 chairs?

Elza [17]

I hour because, one of the 5 carpenters built one chair in one hour, so one of the 100 carpenters would build one chair in one hour, there are only 95 more carpenters, nothing else different.
Hope I helped!

7 0

2 years ago

Read 2 more answers