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natulia [17]
2 years ago
5

Hospital administrator Jake Rosen was recently convicted for fraud he committed against his employer, Cedar Hospital Systems. Ov

er a period of six years, Jake allegedly made payments to a dummy company for maintenance charges while simultaneously running a scheme with maintenance contractors where he either paid them for work never performed or overpaid them for work. The skyscraper where Jake worked was only 10 years old. Maintenance charges rose from $5.2 million in 1994 to $16.4 million in 2000. It was worth noting that the judge on the case questioned whether Cedar Hospital Systems deserved less than full restitution for failing to notice the problem. However, it was determined that federal law on restitution does not allow such charges, so Jake Rosen will be making monthly payments toward the alleged $8 million he stole until he makes full restitution after leaving prison. He was able to quickly repay $3.2 million of the theft with assets recovered by the government, including two homes and a nice yacht. Not bad for a man who was supposed to be making $90,000 per year.
1. In what specific types of fraud was Jake Rosen engaged?
2. The judge questioned whether the hospital should be held partially responsible for not having de- tected the fraud. What could the hospital have done to prevent or detect the fraud earlier?
Mathematics
1 answer:
dexar [7]2 years ago
6 0

Step-by-step explanation:

Employee frauds are one of most common form of frauds which can be detected in a company. There can be many types or forms of employee frauds.  

the major types are:

• Asset Misappropriation

• Bribery and Corruption

• Data theft

• Vendor Fraud

• Payroll Fraud

• Accounting Fraud

2. The hospital could have detected the fraud going on earlier if they had consulted the help of an audit firm this could have helped exposed the fraud earlier.

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-67b + 6 ≤ 9b + 43 solve for b
qaws [65]

Answer:

b ≥  -(37/76)

Step-by-step explanation:

5 0
2 years ago
باستعمال log4 2=0.5 فإن قيمة log4 32 هي
11Alexandr11 [23.1K]

Answer:

\mathbf{\log_432}=2.5

Step-by-step explanation:

\log_42=0.5

حن بحاجة إلى إيجاد\log_432

دع\log_432=x

\log_42\times 2\times 2\times 2\times 2=x

\Rightarrow x=\log_42^5

\Rightarrow x=5\log_42   [\because \log_ab^x=x\log_ab]

\Rightarrow x=5\times0.5

\Rightarrow x=2.5

\mathbf{\therefore\log_432=2.5}

7 0
2 years ago
Study the steps used to solve the equation. Given: StartFraction c Over 2 EndFraction minus 5 equals 7 Step 1: StartFraction c O
Bas_tet [7]

Answer:

  1. addition property of equality
  2. integers are closed to addition
  3. identity element
  4. multiplication property of equality
  5. commutative property of multiplication; reals are closed to multiplication; identity element

Step-by-step explanation:

<u>Given</u>:

  c/2 -5 = 7

  Step 1: c/2 -5 +5 = 7 +5

  Step 2: c/2 +0 = 12

  Step 3: c/2 = 12

  Step 4: 2(c/2) = 12(2)

  Step 5: c = 24

<u>Find</u>:

  The property that justifies each step of the solution.

<u>Solution</u>:

  Step 1: addition property of equality (lets you add the same to both sides)

  Step 2: integers are closed to addition

  Step 3: identity property of addition (adding 0 changes nothing)

  Step 4: multiplication property of equality

  Step 5: closure of real numbers to multiplication; identity property of multiplication

_____

It is hard to say what "property" you want to claim when you simplify an arithmetic expression. Above, we have used the property that the sets of integers and real numbers are closed to addition and multiplication. That is, adding or multiplying real numbers gives a real number.

In Step 5, we can rearrange 2(c/2) to c(2/2) using the commutative property of multiplication. 2/2=1, and c×1 = c. The latter is due to the identity element for multiplication: multiplying by 1 changes nothing.

Apart from the arithmetic, the other properties used are properties of equality.  Those let you perform any operation on an equation, as long as you do it to both sides of the equation. The operations we have performed in this fashion are adding 5 and multiplying by 2.

8 0
2 years ago
Read 2 more answers
The following table shows the salary of 7 people in an office last year.
kotegsom [21]

Answer:

a.  £24,714.29

b. £16,833.33

Step-by-step explanation:

The calculation of mean income is given below:-

Mean income = Total addition of salaries ÷ Number of workers

= £9,500 + £25,000 + £13,250 + £72,000 + £12,750 + £29,500 + £11,000

= £173,000 ÷ 7

= £24,714.29

Now,

the Mean income excluding Deva's salary:

= Formula of Mean income

= Total addition of salaries excluding Deva salary ÷ Number of workers

= (£9,500 + £25,000 + £13,250 + £12,750 + £29,500 + £11,000) ÷ 6

= £101,000 ÷ 6

= £16,833.33

7 0
2 years ago
HJ is twice JK. J is between H and K. If HJ= 4x and HK=78, find Jk.
ss7ja [257]
You'll find it easier to understand if you illustrate the problem as what is shown in the attached picture. From the illustration and the problem description, two equations can be formulated:

HJ = 2JK
HJ + JK = HK

2JK + JK = 78
3JK = 78
JK = 78/3
JK = 26

6 0
2 years ago
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