I'll just show you how to make a frequency table using the above data.
We will group the data into class intervals and determine the frequency of the group.
<span>8 12 25 32 45 50 62 73 80 99 4 18 9 39 36 67 33
</span>
smallest data value = 4
highest data value = 99
difference = 99 - 4 = 95
number of data = 17
Let us assign a class interval of 20.
Class Interval Tally Frequency
0-20 8, 12, 4, 18, 9, 5
21-40 25, 32, 39, 36, 33 5
41-60 45, 50, 67 3
61-80 62, 73, 80 3
81-100 99 1
That is how a frequency table look like. Usually, under the Tally column, tick marks are written instead of the numbers but for easier monitoring, I used the numbers in the data set.
Answer:
The answer to your question is given below.
Step-by-step explanation:
To know the correct answer to the question, do the following:
√12 + √108
= 12^½ + 108^½
= 4^½ • 3^½ + 36^½ • 3^½
Factorise
3^½ (4^½ + 36^½)
Recall:
4^½ = √4 = 2
36^½ = √36 = 6
Therefore,
3^½ (4^½ + 36^½) = 3^½ (2 + 6)
= 3^½ • 8
To determine the number of modules that is in each story, we simply divide the number of modules by the number of stories.
= 140 / 14
Simplifying,
= 10 modules / story
Therefore, by even distribution we note that there are 10 modules per story.
The scientific notation of 832,000 is <span>8.32 × (10)to the fifth power.
Have a great day!
</span>
Answer:
(a) 
(b) 100
Step-by-step explanation:
Solving (a):
Given
Shape: Rectangle

Required
Calculate the perimeter.
Area is calculated as:

Where
and 
Substitute 64.8 for Area

Make L the subject:

Perimeter is calculated as:

Substitute 64.8/W for L


To solve further, we take the derivative of P and set it to 0, afterwards.

Set to 0

Collect Like Terms

Cross Multiply:

Divide through by 2

Take square roots


Recall that:

So:


The perimeter is:



Solving (b):
Given
((1 Group of 10 tenths) and (1 group of 8 tenths))/(6 groups of 3 tenths)
Required
Solve

So, the expression becomes:
((1 Group of
) and (1 group of
))/(6 groups of
)
This gives:
((1 Group of
) and (1 group of
))/(6 groups of
)
Group means product, so the expression becomes:

And, as used here means addition

Simplify:



