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ankoles [38]
2 years ago
9

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 l

b), and a music player (0.4 lb). Using the inequality x Less than or equal to 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed? Explain.
Mathematics
1 answer:
slamgirl [31]2 years ago
5 0

Answer:

She will leave an extra video game which weighs 0.25lb

Step-by-step explanation:

Li wants to add these items to her suitcase: a hairdryer (1.25 lb), a hand-held video game (0.6 lb), an extra video game (0.25 lb), and a music player (0.4 lb). Using the inequality x ≤ 2.25, can she add all these items to the suitcase? If not, what could be left out to be closest to the maximum weight allowed?

Solution:

Weight of the items

hairdryer = 1.25 lb

hand-held video game = 0.6 lb

an extra video game = 0.25 lb music player = 0.4 lb

The total weight of the items

= 1.25lb + 0.25lb + 0.6lb + 0.4lb

= 2.5 lb.

Total weight - required weight

= 2.5lb - 2.25lb

= 0.25lb

2.5lb is 0.25lb greater than 2.25lb

Therefore, not all items can be added.

She has to leave out an item equivalent to 0.25lb

Item equivalent to 0.25lb is the extra video game

If Li leaves out the extra game, which weighs 0.25 lb, she’d have the maximum weight allowed.

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2 years ago
A thumbtack that is tossed can land point up or point down. The probability of a tack landing point up is 0.2. A simulation was
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Answer:

Option C: 0.28

Step-by-step explanation:

This is a binomial probability distribution problem.

Now, we want to find the probability that at least 2 thumbtacks land pointing up when 5 thumbtacks are tossed. This is written as;

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Thus;

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Answer:

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Step-by-step explanation:

We are given the following information:

We treat subscription order with an entry form as a success.

P(subscription order with an entry form) = 0.4

Then the number subscription order with an entry form follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 14

We have to evaluate:

P(x \geq 4) =1 - P(x = 0) - P(x = 1) - P(x = 2) - P(x = 3) \\= 1 - (\binom{14}{0}(0.4)^0(1-0.4)^{14} + \binom{14}{1}(0.4)^1(1-0.4)^{13} + \binom{14}{2}(0.4)^2(1-0.4)^{12} + \binom{14}{3}(0.4)^3(1-0.4)^{11})\\=1-(0.0007+0.0074+0.0317+0.0846)\\= 0.8756

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ANSWER

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EXPLANATION

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