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Maksim231197 [3]
2 years ago
13

A flush in the card game of poker occurs if a player gets five cards that are all the same suit​ (clubs, diamonds,​ hearts, or​

spades). Complete parts​ (a) and​ (b) to obtain the probability of being dealt a flush in five cards. ​
A) Initially concentrate on one​ suit, say diamonds. There are 13 diamonds in a deck. Compute​ P(five diamonds​)=​P(first card is diamonds and second card is diamonds and third card is diamonds and fourth card is diamonds and fifth card is diamonds​).
A flush can occur it a player receives five clubs or five diamonds or five hearts or five spades. Compute P(five clubs or five diamonds or five hearts or five spades). Note that the events are mutually exclusive.
Mathematics
1 answer:
Pachacha [2.7K]2 years ago
5 0

Answer:

whats the question here i dont know how to help right now

Step-by-step explanation:

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In a normally distributed data set a mean of 55 where 95% of the data fall between 47.4 and 62.6, what would be the standard dev
tresset_1 [31]

Answer:

The standard deviation of that data set is 3.8

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 55

95% of the data fall between 47.4 and 62.6. This means that 47.4 is 2 standard deviations below the mean and 62.6 is two standard deviations above the mean.

Using one of these points.

55 + 2sd = 62.6

2sd = 7.6

sd = 7.6/2

sd = 3.8

The standard deviation of that data set is 3.8

6 0
2 years ago
3 ½ times as many guests arrived as were expected. If 105 guests were unexpected, how many guests were expected ?
lara [203]
Let x be the expected number Number arriving = 3•5 x Unexpected number 2•5 x 2•5 x = 105 10x = 420 x = 42______Option D
8 0
2 years ago
According to a 2011 report by the United States Department of Labor, civilian Americans spend 2.75 hours per day watching televi
marusya05 [52]

Answer:

Step-by-step explanation:

Confidence interval is written in the form, sample mean ± margin of error

The sample mean is an estimator for the population mean. The confidence level is used to express how confident we are that the population mean is within the calculated confidence interval. The lower limit of the given confidence interval is 2.619 hours/day while the upper limit of the confidence interval is 3.401 hours/day

Therefore, the INVALID interpretations of the 95% confidence interval are

A. About 95% of all Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.

B. There is a 95% chance that, on average, Cal Poly students spend between 2.619 and 3.401 hours/day watching TV.

D. In the long run, 95% of the sample means will be between 2.619 and 3.401 hours.

E. None of the above.

3 0
2 years ago
Jessica is 5 years older than her sister Jenna. Jenna tells her sister that in 5 years, she will be as old as Jessica was 5 year
Mamont248 [21]

Answer: equations 1,3,4 and 5 stated has solutions.

Step-by-step explanation:

From the question, (x + 5) + 5 = (x + 5) + 5

The equations that represent the situation are:

1. x + 5 = (5 − x) − 5 :which has one solution

2. x + 5 = (x + 5) − 5 : many solutions

3. x + 5 = (x + 5) − 5: no solution

4. x + 5 = (5 − x) − 5 : many solutions

5. (x + 5) + 5 = (x + 5) + 5: many solutions

Equation 2 has no solution. While the other equations have one and more than one solutions.

6 0
2 years ago
The table shows the concentration of a reactant in the reaction mixture over a period of time.
saveliy_v [14]
<h3>Option C</h3><h3>The average rate of the reaction over the entire course of the reaction is: 2.0 \times 10^{-3}</h3>

<em><u>Solution:</u></em>

Average rate is the ratio of concentration change to the time taken for the change

Average\ rate = \frac{ \triangle c }{\triangle t }

The concentration of the reactants changes 1.8 M to 0.6 M

here, the time interval given is 0 to 580 sec

Therefore,

Average\ rate = \frac{1.8-0.6}{580} \\\\Average\ rate = \frac{1.2}{580} \\\\Average\ rate \approx 2.0 \times 10^{-3}

Thus option C is correct

5 0
2 years ago
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