The percentage in increase can be calculated as follows:
% of increase = (difference between new and old amounts / old value) *100
For Dario:
difference in values = 413 - 350 = 63
% of increase = (63/350)*100 = 18%
For Monica:
difference in values = 270 - 225 = 45
% of increase = 20%
Therefore,
Monica has higher percent of increase.
The difference in percents = 20% - 18% = 2%
<u><em>Answer:</em></u>
The longest bread stick is approximately 16 in
<u><em>Explanation:</em></u>
The diagram representing the tray is shown in the attached image
From the diagram, we can note that the diagonal of the tray represents the hypotenuse of a right-angled triangle having legs 9.5 in and 13 in
<u>Therefore, to get the length of the hypotenuse, we can use the Pythagorean equation which is as follows:</u>
c² = a² + b²
where c is the length of the hypotenuse and a and b are the length of the two legs
<u>Substitute with the givens in the above equation to get the length of the hypotenuse as follows:</u>
c² = (9.5)² + (13)² = 259.25
c = 16.1 in which is approximately 16 in
<u>From the above, we can conclude that:</u>
The longest bread stick that can be fit straight along the diagonal of the tray is approximately 16 in
Hope this helps :)
Hi there! Osvoldo did not meet his goal.
(In my answering I suppose you mean 30%, 220 grams of carbohydrates and 55 grams of whole grains, if this is incorrect, please let me know)
Today Osvoldo ate 220 grams of carbohydrates.
10 % of 220 is 22 (divide by 10), and therefore 30 % of 220 is 22 * 3 = 66.
If at least 66 grams of Osvoldo's total consumption consisted of whole grains, he would have met his goal. However, he only ate 55 grams of whole grains (which is less than 66), and therefore he did not meet his goal.
Answer: 2
<u>Explanation:</u>
A pond had 60 fish but 10 were added so now the pond has 70 fish.
The probability of choosing a carp is 1/2 so
= 35 are now carp.
There were 27 carp and now there are 35 carp so 8 carp were added.
10 fish were added and 8 of them were carp so 2 of them were tench.