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2 years ago

10

Planes S and R both intersect plane T Which statements are true based on the diagram? Select three options OPlane S contains poi

nts B and E. The line containing points A and B lies entirely in plane T B ULine v intersects lines x and y at the same point ULine z intersects plane S at point C OPlanes R and T intersections at line y.

1 answer:

jeka942 years ago

5 0

Answer:

Options (2), (4) and (5)

Step-by-step explanation:

Option (1).

Planes S contains points B and F.

False.

(Point B lies on plane S and point F lies on plane R)

Option (2).

The line containing points A and B lie on the plane T.

True.

(points A and B lie on plane T)

Option (3).

Line v intersects lines x and y at the same plane.

False.

Option (4).

Line z intersects plane S at point C.

True.

Option (5).

Planes R and T intersect at line y.

True.

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Decide, without calculation, if each of the integrals below are positive, negative, or zero. Let D be the region inside the unit

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The integrals over B and T will be positive. Keeping $y$ fixed, $xe^x$ is strictly increasing over D as $x$ increases, so the integrals over $x$ (i.e. the bottom/top left quadrants of D) is negative but the integrals over $x>0$ are *more* positive.

The integrals over R and L are zero. If we take $f(x,y)=xe^x$ , then $f(x,-y)=f(x,y)$ , which is to say $f$ is symmetric across the $x$ -axis. For the same reason, the integral over all of D is also zero.

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2 years ago

What is 119,000,003 in expanded form

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100,000,000+10,000,000+9,000,000+3

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2 years ago

Given: mKP=2mIP, mIVK =120°<br> Find: m∠KJL.

anzhelika [568]

Answer:

<h2>The measure of angle KJL is 40°.</h2>

Step-by-step explanation:

Givens

$m(KP)=2m(IP)$

$m(IVK)=120\°$

Notice that

$m(KP)+m(IP)+m(IVK)=360\°$ , by definition sum of arcs.

Replacing given values, we have

$2m(IP)+m(IP)+120\°=360\°\\3m(IP)=360\° - 120\°\\m(IP)=\frac{240\°}{3}\\ m(IP)=80\°$

Which means $m(KP)=2(80\°)=160\°$

Notice that arc KP is the subtended arc by angle KJL.

We know that the angle formed by a tangen and a secant is equal to one-half of the difference of the intercepted arcs.

$m\angle KJL = \frac{1}{2} (m(KP)-m(IP))\\m \angle KJL = \frac{1}{2}(160\° - 80\° )=\frac{1}{2}(80\°)=40\°$

Therefore, the measure of angle KJL is 40°.

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2 years ago

Of the 500 sample households in the previous exercise, 7 had three or more large-screen TVs. (a) The percentage of households in

likoan [24]

Answer:

a) The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

$\hat p=\frac{7}{500}=0.014$

And that represent the 1.4%.

b) And the 95% confidence interval would be given (0.00370;0.0243).

And the % would be between 0.37% and 2.43%.

Step-by-step explanation:

Data given and notation

n=500 represent the random sample taken

X=7 represent the households with three or more large-screen TVs

$\hat p=\frac{7}{500}=0.014$ estimated proportion of households with three or more large-screen TVs

$\alpha=0.05$ represent the significance level (no given, but is assumed)

z would represent the statistic (variable of interest)

p= population proportion of households with three or more large-screen TVs

Part a

The percentage of households in the town with three or more largescreen TVs is estimated as :

The best estimation for the population proportion is :

$\hat p=\frac{7}{500}=0.014$

And that represent the 1.4%.

Part b

Yes is possible. We hav that $np>10$ and $n(1-p)>10$ so we have the assumption of normality to find the interval.

The confidence interval would be given by this formula

$\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}$

For the 95% confidence interval the value of $\alpha=1-0.95=0.05$ and $\alpha/2=0.025$ , with that value we can find the quantile required for the interval in the normal standard distribution.

$z_{\alpha/2}=1.96$

And replacing into the confidence interval formula we got:

$0.014 - 1.96 \sqrt{\frac{0.014(1-0.014)}{500}}=0.00370$

$0.014 + 1.96 \sqrt{\frac{0.014(1-0.014)}{500}}=0.0243$

And the 95% confidence interval would be given (0.00370;0.0243).

And the % would be between 0.37% and 2.43%.

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2 years ago

Suppose a term of a geometric sequence is a4 = 121.5 and the common ratio is 3. write the formula for this sequence in the form

9966 [12]

The rule of the <span>geometric sequence is $a* r^{n-1}$
a ⇒⇒⇒ </span><span>the first term
r ⇒⇒⇒ </span><span>common ratio

Given: the fourth term </span>(a4) <span>= 121.5 and the common ratio = 3 and n = 4

∴</span><span> $121.5 = a* 3^{4-1}$
∴ a = 121.5/3³ = 121.5/27 = 4.5

So, T</span><span>he formula for this sequence will be</span><span> $4.5 * 3^{n-1}$ </span>

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2 years ago

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