Answer:
Gene is present on the X chromosome.
Explanation:
The two main types of chromosomes are autosomes and sex chromosomes. Autosomes regulates the functioning of the body but do not play role in determining the sex of an individual. The sex chromosomes distinguishes between the male and female.
The linkage of sex chromosomes is present in Drosophila as well. The cross between the F1 generation leads to both the red and white eyed flies because the eye color gene is present on the X chromosome. The males contain only one X chromosome and the presence of recessive gene results in the white color whereas in females both the X chromosomes must contain recessive gene for the white color.
Thus, the answer is gene involved is on the X chromosome.
The right options are;
are disease-causing microorganisms
can be fatal
A pathogens is any substance or organism especially microorganisms that are capable of causing diseases. Pathogens include; bacteria, viruses, protozoa or fungi. Microorganisms are not considered to be pathogenic until they have reached a population size that is large enough to cause disease. Pathogens can be fatal and can be treated. Pathogens are diverse and they occupy essentially every environment.
Answer:
Sodium and water move into the cell
Explanation:
Sodium and water move into the cell. This is because
Cellular damage result in failure of the Na+/k+ pump, allowing movement of sodium ions into the cell. This concentration of sodium pulls water in, resulting in hydropic swelling. Cellular damage results in the cell's inability to perform normal metabolic functions because APT decreases and Osmotic finally pressure increases.
Hi!!! I think the answer is B! Have a great rest of the day!!!
Answer:
1. heterozygous yellow and star
2. 37
3. 1/8
4. 168
5. 1/4
Explanation:
Given ,
In f1 generation a cross is made between a true breeding black star bellied sneetch mated with a true breeding yellow starless sneetch
yySS x YYss
It is taken as - Y (yellow) is dominant over y (black)
and S (star) is dominant over s (starless)
1. F1 Generation
Genotype of parents yySS X YYss
gametes - yS, yS, Ys, Ys
All 16 offspring will have genotype YySs
phenotype would be heterozygous yellow and star
2. F2 generation cross
YySs X YySs
YS Ys yS ys
YS YYSS YYSs YySS YySy
Ys YYSs YYss YySs Yyss
yS YySS YySs yySS yySs
ys YySs Yyss yySs yyss
Genotype of offspring are –
YYSS – 1
YYSs – 2
YySS – 2
YySs – 4
YYss- 1
Yyss- 2
yySS – 1
yySs- 1
yyss- 1
2. Out of 16, 2 are black star bellied sneetches . Which means only 1/8 are black star bellied sneetches
So out of 300, 37 are black star bellied sneetches
3. Only 2 out of 16 are true breeding. i.e 1/8
4. 9 out of 16 are yellow star bellied sneetches, so out of 300, 168 are yellow star bellied sneetches
5. 4 out of 16 are true breeding yellow. Thus, ¼ are true breeding
