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2 years ago

What must 111,111,102 be divided by to get 9 as the quotient and 0 as the remainder?

1 answer:

5 0

ANSWER: 12,345,678

EXPLANATION:
we can work backwards by figuring out what 9(the answer) is multiplied by to get 111,111,102 (the starting number) we can do this by dividing by 9:

111,111,102/9 = 12,345,678

so: 9 * 12,345,678 = 111,111,102
which also means

111,111,102/12,345,678 = 9 (with 0 as a remainder)

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The price that a company charged for a basketball hoop is given by the equation 50 - 5x^2 where x is the number of hoops that ar

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Answer: The correct option is first, the number of basketball hoops did the company previously produce to make the same profit is 1.3 million hoops.

Explanation:

Let the number of basketball hoops did the company previously produce to make the same profit be x.

Total Revenue = Price * Quantity

The total revenue in million dollars is,

$\text{Total Revenue}=(50-5x^2)x$

$\text{Total Revenue}=50x-5x^3$

The total cost in million dollars is,

Total Cost = One unit cost * Quantity

$\text{Total Cost}=30x$

Profit = Total Revenue - Total Cost

$\text{Profit}=50x-5x^3-30x$

The profit is 15 million.

$15=20x-5x^3$

$5x^3-20x+15=0\\x^2-4x+3=0\\(x-1)(x^2+x-3)=0$

The value of x is 1 and $\frac{-1\pm \sqrt{13}}{2}$ .

The production is always positive therefore the value of x either 1 or 1.3. Since 1 million is not available in the options therefore the the correct optin is 1.3 million hoops.

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2 years ago

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Six teachers and 12 students volunteer for a committee to discuss extra-curricular activities. How many committees of 5 people c

Alex17521 [72]

Answer:

a) $X=3300$

b) $Y=7770$

Step-by-step explanation:

From the question we are told that:

Number Teachers $T=6$

Number Student $S=12$

Number in committee $n=5$

a) Generally the equation for exactly 3 students on the committee is mathematically given by

$X=^{S}C_3*^{T}C_3$

$X=^{12}C_3*^{6}C_3$

$X=3300$

b) Generally the equation for at least one teacher and at least one student on the committee is mathematically given by

Total Ways-(no of ways of selection no teacher or student)

Where total Ways

$T=^{(6+12)}C_5$

$T=8568$

Therefore

$Y=8568-^{6}C_0*^{12}C_5+^{12}C_0*^{6}C_5$

$Y=8568-798$

$Y=7770$

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2 years ago

The word geometry has eight letters. three letters are chosen at random. what is the probability that two consonants and one vow

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Answer:

0.536 is the required probability.

Step-by-step explanation:

We have been given the word the word "GEOMETRY"

we have to find the probability that two consonants and one vowel are chosen:

Number of consonants are: 5

Number of vowels are: 3

Hence, The required probability is: $\frac{^5C_2\cdot ^3C_1}{^8C_3}$

Using: $^nC_r=\frac{n!}{(r!)(n-r)!}$

$\frac{\frac{5!}{3!\cdot 2!}\cdot\frac{3!}{1!\cdot 2!}}{\frac{8!}{3!\cdot 5!}}$

Simplifying the above expression:

$\frac{\frac{5\cdot 4\cdot 3!}{3!\cdot 2}\cdot {\frac{3\cdot 2!}{2!}}}{\frac{8\cdot 7\cdot 6\cdot 5!}{5!\cdot 3\cdot 2}}$

Further simplification after cancelling out the common terms we get:

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Hence, Option 1 is correct.

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Answer:

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