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Furkat [3]
2 years ago
13

The random variable Y is normally distributed with a mean of 470, and the value Y=340 is at the 15th percentile of the distribut

ion. Of the following, which is the best estimate of the standard deviation of the distribution?
A) 125
B) 135
C) 145
D) 155
E) 165
Mathematics
1 answer:
adell [148]2 years ago
4 0
The empirical rule says that about 68% of any normal distribution lies within one standard deviation of the mean. This leaves 32% of the distribution that lies outside this range, with about 16% to either side.

At the 16th percentile, there is a value of Y=y such that

\mathbb P(Y

where \sigma is the standard deviation for the distribution, and Z is the random variable corresponding to the standard normal distribution. This value of y would correspond roughly to a z-score of Z=-1.

You're told that Y=340 lies at the 15th percentile, so that

\mathbb P(Y

Roughly, then, it'd be fair to say that y\approx340. So you have

\dfrac{340-470}\sigma\approx-1\implies\sigma\approx130

which falls between (A) and (B). To narrow down the choice, notice that y would have be slightly larger than 340 in order to have \mathbb P(Y. This brings y closer to the mean, and thus suggests the standard deviation for the distribution is actually smaller than our approximation.

This tells us that (A) is the answer.
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Which part of the proof does the fourth statement and reason represent?
denis-greek [22]

Answer:

Option B is correct.

Reason:It is an argument

Step-by-step explanation:

Given: AB \cong BC  and BC \cong EF

By transitive property:  a = b  and b = c then, a =c

⇒AB \cong EF

AB = EF                                [def of \cong segment]

By Segment Addition Postulate states that given  two points A and C, and a third point B lies on the line segment AC if and only if the distances between the  points satisfy the equation

AB + BC = AC.

Since, the line segment EG , F lies on the line segment;

then, by segment addition postulates we have;

EG = EF + FG

By substitution AB=EF

⇒ EG = AB + FG                     hence proved!

Since, in the fourth statement reason is:  It is an argument

3 0
2 years ago
oshua tracks the points he scores in 10 basketball games. In two games Joshua scored 8 points each, in one game he scored 3 poin
Anna71 [15]
I believe the answer would be 4.2.

Add all the points together and divide by 10
3 0
2 years ago
Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from​ B, a distance o
g100num [7]

Answer:

The value  is  k =109.6 \ miles

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

   The distance from city A to B is   AB =  467.3 miles

   The bearing from B to  C is  \theta_{BC} =  N 28.7E

   The bearing from B to  A is  \theta_{BA} =  N 60.7E

   The  bearing from A to  B is   \theta_{AB} =  S60.7W

    The  bearing from A to  C is   \theta_{AC} =  S79.1W

Generally from the diagram

     \theta_A  =  180 - 60.7 -79.1

=>  \theta_A  =  40.2 ^o

Also

     \theta_B  =  32^o

and  

      \theta_C  =  180 - (\theta_A  +\theta_B )

=>   \theta_C  =  180 - (40.2  + 32 )

=>   \theta_C  =  107.8 ^o

Generally according to Sine Rule

     \frac{BC}{sin (\theta_A)}  = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}

=>   \frac{BC}{sin (40.2)}  = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}    

So

     \frac{BC}{sin (40.2)}  = \frac{467.3 }{sin (107.8)}

=>  BC = 316.8 \ miles

Also  

    \frac{CA}{sin (32)} =  \frac{467.3 }{sin (107.8)}

    CA = 260 .1 \ miles

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct​ flight is mathematically represented as

      k = [CA +BC]  - AB

=>     k = [260 .1 +316.8]- 467.3

=>  k =109.6 \ miles

4 0
2 years ago
Max invests some money in a savings bond.
WITCHER [35]

Answer:

£288150

Step-by-step explanation:

We'll use the formula

PRT/100= interest

But in this case we are looking for principal P

Rate= 2%

Interest= £5763

T=1

P= (I*100)/(RT)

P= (5763*100)/(2*1)

P= 288150

The principal is £288150

5 0
2 years ago
The points (3,9) and (-3,-9) lie in which quadrants?
kumpel [21]

Answer:

Quadrant I and III

Step-by-step explanation:

The coordinate (3,9) is all positive, therefore it lies in quadrant I.

The coordinate (-3,-9) is all negative, therefore it lies in quadrant III.

3 0
2 years ago
Read 2 more answers
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