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MAXImum [283]
1 year ago
5

Allen Construction purchased a crane 6 years ago for $130,000. They need a crane of this capacity for the next 5 years. Normal o

peration costs $35,000 per year. The current crane will have no salvage value at the end of 5 more years. Allen can trade in the current crane for its market value of $40,000 toward the purchase of a new one, which costs $150,000. The new crane will cost only $8,000 per year under normal operating conditions and will have a salvage value of $55,000 after 5 years. If MARR is 20%, determine which option is preferred
Business
1 answer:
Korvikt [17]1 year ago
5 0

Answer:

<u>For retaining of Old Machine Equipment</u>

Price of old equipment 3 yrs ago = $130,000

O & M cost per year = $35,000

Using the Cash flow approach

End of year   Cash flow 1   Old equipment

0                            $0            Initial Cash flow

1                         -$35,000     O & M cost per year

2                        -$35,000     O & M cost per year

3                        -$35,000     O & M cost per year

4                        -$35,000     O & M cost per year

5                        -$35,000     O & M cost per year

Hence, Annual worth = Initial cash flow + Annual cost

Annual worth = 0 - $35,000

Annual worth = -$35,000

<u>For buying of new equipment</u>

Cost of buying new crane = $150,000

Market value of old crane = $40,000

Time = 5 years

O & M cost per year = $8,000

Salvage value = $55,000

MARR = 20%

Using the Cash flow approach

End of year   Cash flow 1   New equipment

0                         $110,000    -$150,000 + $40,000

1                         -$8,000     O & M cost per year

2                        -$8,000     O & M cost per year

3                        -$8,000     O & M cost per year

4                        -$8,000     O & M cost per year

5                        $47,000     -$8,000 + $55,000

Annual worth = Initial cash flow + Annual cost + Salvage value

Annual worth = -$110,000(A/P 20%,5) - $8,000 + $55,000(A/P 20%,5)

Annual worth = -$110,000*(0.334) - $8,000 + $55,000*(0.134)

Annual worth = -$36,781.77 - $8,000 + $7,390.88

Annual worth = -$37,908.88

Conclusion: We should retain the old machine as it is more favorable than purchase of new equipment

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7 0
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