Noah says that to find 20% of a number he divides the number by 5. For example, 20% of 60 is 12, because 60÷5=12. Does Noah’s me
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Answer:
A)
B) 89.157 million tons.
C) In year 2017.
Step-by-step explanation:
We have been given that world poultry production was 77.2 million tons in the year 2004 and increasing at a continuous rate of 1.6% per year.
A). We know that a continuous growth function is in form , where,
a = Initial value,
k = Growth rate in decimal form.
Upon substituting our given values, we will get:
Therefore, our required function would be , where, P represents world poultry production, in million tons, as a function of the number of years, t, since 2004.
B) To find the world poultry production in the year 2013, we will substitute in above formula as:
Therefore, the world poultry production in the year 2013 would be 89.157 million tons.
C) To find the number of years it will take for world poultry production to be over 95 million tons, we will equate our function with 95 as:
Divide both sides by 77.2:
Take natural log of both sides:
Divide both sides by 0.016:
Therefore, 13 years after in 2017 world poultry production goes over 95 million tons.
Answer:
a)
b)
c)
And we can find the usual limits with:
And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.
d) The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.
And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.
Step-by-step explanation:
We have the following data:
11.8 10.3 10.7 10.6 11.5 8.3 10.5 10.9 10.7 11.2
Part a
We can calculate the sample mean with the following formula:
And if we replace we got:
For the median we need to sort the values on increasing order and we have:
8.3 10.3 10.5 10.6 10.7 10.7 10.9 11.2 11.5 11.8
Since n =10 we can calculate the median as the average between the 5th and 6th position of the dataset ordered and we got:
The mode would be the most repeated value on this case:
Part b
The range is defined as and if we replace we got:
We can calculate the standard deviation with the following formula:
And if we replace we got:
Part c
For this case we can use the IQR method in order to determine if 8.3 is an outlier or not.
We can calculate the first quartile with these values: 8.3 10.3 10.5 10.6 10.7 10.7 and
And for the Q3 we can use: 10.7 10.7 10.9 11.2 11.5 11.8 and we got
Then we can find the IQR like this:
And we can find the usual limits with:
And since 8.3 <9.8 we can consider this value too low or as an outlier for this case.
Part d
The mean for this case was 10.65 and the usual values are between 9.8 and 11.3, so as we can see all are above the specified value of 6 minutes, and we can conclude that the times are not satisfying the quality standards for this case.
And they should be considered apply some strategies to reduce the response time, adding more stations around points selected at the city could be useful in order to reduce the response time.