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Mnenie [13.5K]
2 years ago
4

Use separation of variables to find, if possible, product solutions for the given partial differential equation. (Use the separa

tion constant −λ ≠ 0. If not possible, enter IMPOSSIBLE.)
k∂^2u/∂x^2 - u = ∂u/∂t, k>0
Mathematics
1 answer:
Andrei [34K]2 years ago
4 0

Answer:

Following are the solution to this question:

Step-by-step explanation:

differentail equation:

yu_{xy} + u = 0..........(1)  

when u(x,y) = X(x)Y(y)

u_x = \frac{\partial u}{\partial  x} X'Y' \\\\ u_{xy} = \frac{\partial^2 u }{ \partial x\ \partial  y}= X'Y'

by substituting the value we get:

\to \int \frac{Y'}{Y} = -\lambda \int \frac{1}{y} dy\\\\

by solving the value:

\to Y=c_3 y^{-\lambda}\\\\\therefore\ \ c_4=c_2C_3\\\\\to u(x,y) = c_4 e^{\frac{x}{\lambda}} y^{-\lambda}

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