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2 years ago

Use the coordinates of the labeled point to find the point slope equation of the line

Mathematics

1 answer:

Karo-lina-s [1.5K]2 years ago

4 0

Answer:

D. $y + 1 = -2(x - 2)$

Step-by-step explanation:

Point-slope form equation is given as $y - b = m(x - a)$ , where,

(a, b) = a point of the graph.

m = slope of the graph

Find the slope of the graph:

Slope = $\frac{rise}{run} = \frac{-4}{2} = -2$

Using the point (2, -1) and the slope, m, = -2, we can derive the equation in point-slope form by substituting a = 2, b = -1, and m = -2 into $y - b = m(x - a)$ .

✅The equation would be:

$y - (-1) = -2(x - 2)$

$y + 1 = -2(x - 2)$

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Two standardized tests, a and b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×

Romashka [77]

Answer:

(a) The mean score of test A is 1210.

(b) The mean score of test A is 1210.

(d) The value of Q₃ for test A is 1170.

(e) The value of median for test A is 1090.

(f) The value of IQR for test A is 290.

Step-by-step explanation:

The relation between two standardized tests <em>A</em> and <em>B</em> is:

$50A=40B+50$

The equation above approximates the relationship between scores on the two tests.

The summary statistics for test B are as follows:

Lowest Score = 21

Mean score = 29

Standard deviation = 2

Q₃ = 28

Median = 26

IQR = 6

(a)

Compute the lowest score on test A as follows:

$A=40B+50\\=(40\times21)+50\\=890$

Thus, the lowest score on test A is 890.

(b)

Compute the mean score of test A as follows:

<h2> $A=40B+50\\=(40\times29)+50\\=1210$ </h2>

Thus, the mean score of test A is 1210.

(c)

Compute the mean score standard deviation of test A as follows:

<h2> $A=40B+50\\=(40\times2)\\=80$ </h2>

Thus, the standard deviation of test A is 80.

(d)

Compute the value of Q₃ for test A as follows:

$A=40B+50\\=(40\times28)+50\\=1170$

Thus, the value of Q₃ for test A is 1170.

(e)

Compute the value of median for test A as follows:

$A=40B+50\\=(40\times26)+50\\=1090$

Thus, the value of median for test A is 1090.

(f)

Compute the value of IQR for test A as follows:

$A=40B+50\\=(40\times6)+50\\=290$

Thus, the value of IQR for test A is 290.

6 0

2 years ago

Find the equation of the line below if necessary use the slash (/) to indicate a division bar (2,6)(1,3)

777dan777 [17]

Given that the line passes through points:
(2,6), (1,3)
the equation will be given by:
m(x-x1)=y-y1
where
slope, m=(y-y1)/(x-x1)
from the points given:
m=(6-3)/(2-1)=3/1=3
thus the equation will be given by:
using point (1,3)
3(x-1)=y-3
3x-3=y-3
hence
y=3x-3+3
y=3x
Answer: y=3x

7 0

2 years ago

The graphs below have the same shape. What is the equation for the red graph?

Serhud [2]

Your answer would be B because even though it's the same shape the red shape is 2 times bigger.......your exponent 4 stays 4

8 0

2 years ago

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Katie wants to create a rectangular frame for a picture. She has 60 inches of material. If she wants the length to be 3 more tha

Fofino [41]

Answer:

Largest possible length is <em>21 inches</em>.

Step-by-step explanation:

Given:

Total material available = 60 inches

Length to be 3 more than twice of width.

To find:

Largest possible length = ?

Solution:

As it is rectangular shaped frame.

Let length = $l$ inches and

Width = $w$ inches

As per given condition:

$l = 2w+3$ ..... (1)

Total frame available = 60 inches.

i.e. it will be the perimeter of the rectangle.

Formula for perimeter of rectangle is given as:

$P = 2 \times (Width + Length)$

Putting the given values and conditions as per equation (1):

$60 = 2 \times (w+ l)\\\Rightarrow 60 = 2 \times (w+ 2w+3)\\\Rightarrow 60 = 2 \times (3w+3)\\\Rightarrow 30 = 3w+3\\\Rightarrow 3w = 27\\\Rightarrow w = 9 \ inch$

Putting in equation (1):

$l = 2\times 9+3\\\Rightarrow l = 21\ inch$

So, the answer is:

Largest possible length is <em>21 inches</em>.

6 0

2 years ago

A student prepares 150.0 mL of 1.40 M HCl using 35.0 mL of a stock solution. What is the concentration of the stock solution? Us

Gwar [14]

Your answer would be c.6.00 M

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2 years ago

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