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3241004551 [841]
2 years ago
8

1. The rent of a condo unit was ₱1,200.00 for one night, to be shared equally by a group of female friends, who will be having t

heir get together in the condo unit. At the last minute, four people decided not to go to the party, thus raising the cost to each girl by ₱400.00. How many girls attended the get-together?
(With Solutions Please)
Mathematics
1 answer:
zhuklara [117]2 years ago
4 0

Answer:

6 girls were there are first

Step-by-step explanation:

use trial and error. divide 1200 by a random number like 10, and see how much they each had to pay. If we guessed 10, then each girl would hypothetically pay 120 pounds. If four girls left, then 1200/6 would be 200 pounds. there was only a 60 pound increase here, not a 400 pound one.

I checked 1200/6 which equals 200 pounds per girl. If 4 girls left, then it would be 600 pounds for the 2 remaining girls. the rent increased from 200 to 600 which is a 400 pound increase.

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 we would then want to add that to the ratio of the  lawn sprinkler and hose together together which would be 5 minutes for both / 8 minutes for hose
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9 0
2 years ago
Read 2 more answers
a previous analysis of paper boxes showed that the standard deviation of their lengths is 15 millimeters. A packers wishes to fi
vladimir1956 [14]

Answer:

864.36 boxes

Step-by-step explanation:

In the question above, we are given the following values,

Confidence interval 95%

Since we know the confidence interval, we can find the score.

Z score = 1.96

σ , Standards deviation = 15mm

Margin of error = 1 mm

The formula to use to solve the above question is given as:

No of boxes =[ (z score × standard deviation)/ margin of error]²

No of boxes = [(1.96 × 15)/1]²

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8 0
2 years ago
Reyna has 5 coins worth 10 cents each and 4 coins
Zolol [24]

Answer:

The Probability found is:

P =  \frac{13}{18}

Step-by-step explanation:

Let x be the 10 cents coin.

Let y be the 25 cents coin.

We have to find all the possible outcomes

1) First coin = 10 cents, Second coin = 10 cents , so

(x,x) = 20

2) First coin = 10 cents, Second coin = 25 cents , so

(x,y) = 35

3) First coin = 25 cents, Second coin = 10 cents , so

(y,x) = 35

4) First coin = 25 cents, Second coin = 25 cents , so

(y,y) = 50

Find the probability of each outcome:

P(x,x) =  \frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}

P(x,y) =  \frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}

P(y,x) =  \frac{5}{9}\cdot\frac{4}{8}=\frac{20}{72}

P(y,y) = \frac{4}{9}\cdot\frac{3}{8}=\frac{12}{72}

Add all the probabilities where sum is at least 35 i.e P(x,y) , P(y,x) , P(y,y)

P(x,y) + P(y,x) + P(y,y) = \frac{20}{72}+\frac{20}{72}+\frac{12}{72} = \frac{52}{72}=\frac{13}{18}\\

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rita traveled 1250 miles in the first 3 days of her trip. at this rat how long will it take her to travel 1875?
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It will take rita 4.5 days to travel to her destination
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Sylvia invested $500 in an account compounded annually with an interest rate of 8%. Manuel invested $600 in an account with a co
Sav [38]
Syliva
T=72÷8=9 years

Manul
T=72÷7.25=9.9=10 years

Option A
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